Simplify both sides of the inequality, then isolate the variable. That should leave you with x> - 4
Answer:
the relationship between these two angle is they r straight angle.
- 101+3x+4=180°
- 105+3x=180°
- 3x=180-105
- x=75/3
- x=25°
hope it helps
<h2>stay safe healthy and happy.</h2>
I think it would be C because if you rotated it 90 degrees counter clockwise the A of X of x, y would then become negative
Answer:
The answer is 3x+2
Step-by-step explanation:
2(3x-1)-3x+4
I did distributive property on 2(3x-1) how I did that was I multiplied 2 times 3x which is 6x (2 times 3x=6x). Then I multiplied 2 times -1 which equals -2 (2 times -1=-2).
new expression:
6x-2-3x+4
I combined all the numbers with the variables (6x and -3x) and by subtracting both of them you get 3x (6x-3x=3x). After that you combine -2 and 4 which equals 2 (-2+4=2).
This is now the final expression (your answer):
3x+2
Answer:
The required probability is 0.927
Step-by-step explanation:
Consider the provided information.
Surveys indicate that 5% of the students who took the SATs had enrolled in an SAT prep course.
That means 95% of students didn't enrolled in SAT prep course.
Let P(SAT) represents the enrolled in SAT prep course.
P(SAT)=0.05 and P(not SAT) = 0.95
30% of the SAT prep students were admitted to their first choice college, as were 20% of the other students.
P(F) represents the first choice college.
The probability he didn't take an SAT prep course is:
![P[\text{not SAT} |P(F)]=\dfrac{P(\text{not SAT})\cap P(F) }{P(F)}](https://tex.z-dn.net/?f=P%5B%5Ctext%7Bnot%20SAT%7D%20%7CP%28F%29%5D%3D%5Cdfrac%7BP%28%5Ctext%7Bnot%20SAT%7D%29%5Ccap%20P%28F%29%20%7D%7BP%28F%29%7D)
Substitute the respective values.
![P[\text{not SAT} |P(F)]=\dfrac{0.95\times0.20 }{0.05\times0.30+0.95\times0.20}](https://tex.z-dn.net/?f=P%5B%5Ctext%7Bnot%20SAT%7D%20%7CP%28F%29%5D%3D%5Cdfrac%7B0.95%5Ctimes0.20%20%7D%7B0.05%5Ctimes0.30%2B0.95%5Ctimes0.20%7D)
![P[\text{not SAT} |P(F)]\approx0.927](https://tex.z-dn.net/?f=P%5B%5Ctext%7Bnot%20SAT%7D%20%7CP%28F%29%5D%5Capprox0.927)
Hence, the required probability is 0.927
