Question

Help me solve this problem plsssss ​

Answer 1

Answer:

It is a Right angle triangle ,

So, Apply Pythagoras Theorem ,

$y = \sqrt{ {2x}^{2} + {(x + 3)}^{2} }$

$y = \sqrt{4 {x}^{2} + {x}^{2} + 3 + 6x }$

$y = \sqrt{5 {x}^{2} + 6x + 9}$

Now put X =2

$y = \sqrt{5 \times 4 + 6 \times 2 + 9}$

$y = \sqrt{41}$

Hope it helps you...