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Fantom [35]
3 years ago
6

Both similar triangles , solve for x

Mathematics
1 answer:
Lilit [14]3 years ago
3 0

Answer:

51

Step-by-step explanation:

(64/28) X 21 = x-3

48  = x - 3

+3         +3

51

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Find X. 2x + 15 = 20
lakkis [162]

Answer:

x = 5/2     or     x = 2.5

Step-by-step explanation:

To solve for x, we will have to get the equation 2x + 15 = 20 into the form x = _. That will be our answer.

2x + 15 = 20

Subtract 15 from both sides to get rid of the +15 on the left side.

2x = 20 - 15

Simplify.

2x = 5

Divide both sides by 2 to get rid of the coefficient of 2 on the left side.\

x = 5/2 = 2.5

x = 5/2   or    x = 2.5

I hope you find my answer helpful. :)

3 0
4 years ago
Is an angle made of any 2 rays and why?
Kipish [7]
An angle is any two rays that share an endpoint. the reason that last part is important is becasue they could be one ray that starts in seatlle and one ray starting over in new york. these would not for an angle. if i confused you let me know and ill try to clarify.
4 0
3 years ago
Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

5 0
3 years ago
Find the product: (0.45)•(0.008)
Leya [2.2K]

0.45x0.008=0.0036

---

hope it helps

5 0
3 years ago
(4k^5-9k^4+k^3-7k^2-9k+28)/4k-5
vlada-n [284]

Answer:

=k6+ −9 /4  k5+ 1 /4  k4+  −7 /4  k3+  −9 /4  k2+7k−5

Step-by-step explanation:

7 0
3 years ago
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