3 years ago

If 11A=180 then prove that secA×sec2A×sec3A×sec4A×sec5A=32.

Mathematics

1 answer:

Vesnalui [34]3 years ago

8 0

Answer:

u prolly will know if u payed attention in class

Step-by-step explanation:

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3 years ago

If 11A=180 then prove that secA×sec2A×sec3A×sec4A×sec5A=32.​

If 11A=180 then prove that secA×sec2A×sec3A×sec4A×sec5A=32.