Question

Twice the sum of a number, n, and seven is four less than the quotient of a number, n, and three.

Answer 1

Answer:

Step-by-step explanation:

$2(n+7)=\frac{n}{3}-4\\ \\ 2n+14=\frac{n-12}{3}\\ \\ 6n+42=n-12\\ \\ 5n+42=-12\\ \\ 5n=30\\ \\ n=6$