Answer:
a. P(X = 0) = 0.02586
b.
c.
Step-by-step explanation:
From the given information:
a. If the manufacturer stocks 120 components, what is the probability that the 120 orders can be filled without reordering components?
P(X = 0) = 1 × 1 ( 0.97)¹²⁰ ⁻ ⁰
P(X = 0) = 0.02586
b. ) If the manufacturer stocks 122 components, what is the probability that the 120 orders can be filled without reordering components?
(c) If the manufacturer stocks 125 components, what is the probability that the 120 orders can be filled without reordering components?
Answer:
I think Rs and PT
if wrong correct me pls
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