The second one is the correct answer
Answer:
BC is 10 unit
BD is 15 units
Step-by-step explanation:
Here, given the end points of the line segments, we want to calculate BD and DC
Mathematically, the distance between two points can be calculated using the formula;
D = √(x2-x1)^2 + (y2-y1)^2
For BD, we have the following
D = √(14-5)^2 + (14-2)^2
D = √(9)^2 + 12^2
D = √81 + 144
D = √(225)
Distance BD is 15 units
For BC, we have the following
D = √(11-5)^2 + (10-2)^2
D = √(6)^2 + 8^2
D = √100
D = 10
12 over 15
all of them but that one simplify to 2 over 3
Answer:
Step-by-step explanation:
18^y = 4/6 Take the log of both sides
log(18^y) = log(4/6)
log(18^y) = y * log(18)
log (4/6) = - 0.17609
y * log(18) = y * 1.25527
So
y = - 0.17609 / 1.25527
y = - 0.14056
Check
18^-0.14056 = 0.6661 which is close enough to 0.666666666
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z^4 = 8/5 Take the log of both sides.
log(z^4) = log(8/5) Simlplify the left. Take the log of the right.
4 * log(z) = 0.20416 Divide by 4
log(z) = 0.20416 /4
log(z) = 0.051029 Take the antilog of both sides.
z = 10^(0.051029)
z = 1.12467
Check
1.12467 ^ 4 = 1.6 which is what it should be.
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I can't really make out the third one.
