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DedPeter [7]
3 years ago
5

Use the dropdown to complete the following inequality.

Mathematics
1 answer:
bazaltina [42]3 years ago
6 0

Answer:

>

Step-by-step explanation:

b is clearly negative

- - = +

so therefore, subtracting the negative will result in a larger answer than adding a small positive to a negative

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Given that f(x)= x2+3 and g(x)= x+4/3 solve for (f(g(x)) when x =2
Savatey [412]
\bf \begin{cases}
f(x)=x^2+3\\\\
g(x)=x+\cfrac{4}{3}
\end{cases}
\\\\\\
\boxed{x=2}\qquad g(2)=(2)+\cfrac{4}{3}\implies \boxed{g(2)=\cfrac{10}{3}}
\\\\\\
f(~~g(x)~~)=[g(x)]^2+3\implies f(~~g(2)~~)=[g(2)]^2+3
\\\\\\
f(~~g(2)~~)=\left[ \boxed{\frac{10}{3}} \right]^2+3\implies f(~~g(2)~~)=\cfrac{10^2}{3^2}+3
\\\\\\
f(~~g(2)~~)=\cfrac{100}{9}+3\implies f(~~g(2)~~)=\cfrac{100+27}{9}
\\\\\\
f(~~g(2)~~)=\cfrac{127}{9}
7 0
3 years ago
Aster sold 18 oranges if this are 12% of her total oranges how many oranges are not sold​
WITCHER [35]

Answer:

Step-by-step explanation:

So 18 oranges are 12 percent of her total oranges. You can use Ratio to solve this.

O : P

18 : 12                               P = Percentage     O = Orange

1.5 : 1

150 : 100                          

All I did was make the percentage one by dividing both numbers by 12. This makes it 1.5 oranges per percent. Times 1.5 with 100 to make it 100 percent.

7 0
3 years ago
Read 2 more answers
I need help with adding decimals
nasty-shy [4]
When you add the decimals it’s the same as regular adding. You line up the decimals and then add all the way across and when you get to the decimal carry it down
4 0
3 years ago
Read 2 more answers
The volume
Sedaia [141]
\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
&&  y={{ k }}x
\end{array}\\ \quad \\


and also

\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
&&y=\cfrac{{{  k}}}{x}
\end{array}


now, we know that V varies directly to T and inversely to P simultaneously
thus\bf V=T\cdot \cfrac{k}{P}

so     \bf V=T\cdot \cfrac{k}{P}\qquad 
\begin{cases}
V=42\\
T=84\\
P=8
\end{cases}\implies 42=\cfrac{84k}{8}\implies 4=k
\\\\\\
V=\cfrac{4T}{P}\qquad now\quad 
\begin{cases}
V=74\\
P=10
\end{cases}\implies 74=\cfrac{4T}{10}\implies 185=T
7 0
3 years ago
The owner of a baseball stadium found that he sells an average of 586 tickets to each game when he charges an average of $59 per
NeX [460]

Answer:

A: 34574+3280x-24x^2

7 0
3 years ago
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