Answer:
16x+12
Step-by-step explanation:
4 sides
2*(5x-2 )
10x-4
2(3x+8)
6x+16
10x-4+6x+16=16x+12
Hey, I believe the answer to the question is A.
Answer:
The range of the function are the values of height which are from 3, 4, 5, ..., 50
Step-by-step explanation:
The given parameters are;
The height at which the ball is caught = 5 feet
The height at which the ball was hit = 3 feet
The maximum height reached by the ball = 50 feet
The height of the ball given as a function of time is f(t) s = u·t - 1/2·g·t²
Where;
s = 50 feet
g = 9.81 m/s²
Therefore, we have;
50 = u·t - 1/2 × 9.81 × t²
50 = u·t - 4.905 × t²
Therefore, the range are obtainable values for f(t) which range from 3 to 50.
This problem can be solved by algebraic method.
Let
x = the total time spent of all clients in Plan A
y = the total time spent of all clients in Plan B
We represent two variables x and y because there are two plans that won't be happened simultaneously.
On Wednesday, the two workout plans have the total time of 6 hours. We equate
3x + 5y = 6
While on Thursday, the total time is 12 hours. We also equate
9x + 7y = 12
To find x and y, we can use the substitution method. For the first equation, we arrange it in terms of y, that is
5y = 6 - 3x
y = (6 - 3x)/5
Substitute it to the second equation:
9x + (7/5)(6 - 3x) = 12
9x + (42/5) - (21/5)x = 12
Multiply the equation by 5 to cancel the denominator:
45x + 42 - 21x = 60
45x - 21x = 60 - 42
24x = 18
x = 18/24 = 3/4 hours
For y:
3(3/4) + 5y = 6
9/4 + 5y = 6
Multiply the equation by 4 to cancel the denominator:
9 + 20y = 24
20y = 24 - 9
20y = 15
y = 15/20 = 3/4 hours
Hence, each workout plans are done within 3/4 hours (or 45 minutes).
arccos (-1/2) = angle whose cosine = -1/2
= 2pi / 3
Its the first choice.
