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TiliK225 [7]
3 years ago
7

4t+10 < 200, please help me

Mathematics
1 answer:
ddd [48]3 years ago
3 0

Answer:

here's the solution

4t + 10 < 200

4t < 200 - 10

4t < 190

t < 190/4

t < 47.5

hope it helps

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The value of <img src="https://tex.z-dn.net/?f=%5Csin%20%5E%7B-1%7D%5Cleft%28%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%5Cright%29-%5Csi
Mademuasel [1]

Answer:

\displaystyle \frac{\pi}{6}

Explanation:

According to the unit circle, \displaystyle \frac{\pi}{3} and \displaystyle \frac{\pi}{6} are the radian measures you are looking for because all <em>y-coordinates</em> are associated with the <em>sine</em> function, so when evaluating, you will arrive at this:

\displaystyle \boxed{\frac{\pi}{3}} = \frac{\pi}{3} - \frac{\pi}{6}

I am joyous to assist you at any time.

6 0
2 years ago
What is the value of p ?
VLD [36.1K]

Answer:

p = 35

Step-by-step explanation:

180 - 125 = 55

180 - 90 = 90

55 + 90 = 145

180 - 145 = 35

p = 35

6 0
3 years ago
The nth term of a quadratic sequence is:
anzhelika [568]
We can work out the first three terms of this quadratic equation with substitution.
The first term of this sequence is where n=1, we can substitute 1 in for n
y=1^2+2(1)-4
y=1+2-4
y=-1
We can do this for the next two terms as well
y=2^2+2(2)-4
y=4+4-4
y=4
For the last term:
y=3^2+2(3)-4
y=9+6-4
y=11
7 0
4 years ago
Evaluate the expression for the given value of x.<br> 3x + 4 for x= 5
pantera1 [17]
Answer:
19

Explanation:
3x+4
Plug in 5 as x
3(5)+4
=15+4
=19

I hope this helps!
7 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Lilit [14]

Answer:  A & B are the same answer --> 96, max

<u>Step-by-step explanation:</u>

Consider m is the degree of the numerator (top) and n is the degree of the denominator (bottom). Then the horizontal asymptote (H.A.) is based on the relationship between m and n:

  • If m > n, then there is no H.A.
  • If m = n, then y = coefficient of numerator ÷ coefficient of denominator
  • If m < n, then y = 0

In the given problem, m = 1 and n = 1 so the H.A. is:

y=\dfrac{60}{0.625}\quad \rightarrow \quad y=96

This is the maximum number of moose that the forest can sustain at one time.

4 0
4 years ago
Read 2 more answers
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