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pashok25 [27]
2 years ago
7

The value of

n%20%5E%7B-1%7D%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%5Cright%29" id="TexFormula1" title="\sin ^{-1}\left(\frac{\sqrt{3}}{2}\right)-\sin ^{-1}\left(\frac{1}{2}\right)" alt="\sin ^{-1}\left(\frac{\sqrt{3}}{2}\right)-\sin ^{-1}\left(\frac{1}{2}\right)" align="absmiddle" class="latex-formula"> is​
Mathematics
1 answer:
Mademuasel [1]2 years ago
6 0

Answer:

\displaystyle \frac{\pi}{6}

Explanation:

According to the unit circle, \displaystyle \frac{\pi}{3} and \displaystyle \frac{\pi}{6} are the radian measures you are looking for because all <em>y-coordinates</em> are associated with the <em>sine</em> function, so when evaluating, you will arrive at this:

\displaystyle \boxed{\frac{\pi}{3}} = \frac{\pi}{3} - \frac{\pi}{6}

I am joyous to assist you at any time.

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srry if i needed to show the steps

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Step-by-step explanation:ifk

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Step-by-step explanation:

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Which relation represents a function? StartSet (0, 0), (2, 3), (2, 5), (6, 6) EndSet StartSet (3, 5), (8, 4), (10, 11), (10, 6)
postnew [5]

Answer:

<h2>Third set.</h2>

(-2, 2), (0, 2), (7, 2), (11, 2)

Step-by-step explanation:

A function is defined as a relation where each x-value (domain), has only one y-vale assigned (range). If one x-value has more than one image in the range, therefore, that's not a function. So, let's see which relation represents a function.

First: (0, 0), (2, 3), (2, 5), (6, 6).

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Similarly, this relation is not a function, because x=10 has to images, y=11 and y=6.

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This relation is not a function, because the same x-value has multiple images.

Therefore, the right answer is the third set.

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