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Ber [7]
3 years ago
14

Rewrite the expression by factoring out (y-8). 3y^2(y-8)+7(y-8)

Mathematics
1 answer:
guajiro [1.7K]3 years ago
8 0

Answer

(y-8)x(3y^+7)

Step-by-step explanation:

3y^2(y-8)+7(y-8)

(y-8)x(3y^+7)

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"Ten subtracted from the quotient of a number<br> and 5 is 18."
Anika [276]

Answer: n/5 - 10 = 18: this would be the equation. Your answer would be 140.

Step-by-step explanation: Let consider the number as ‘X’

Quotient of a number and 5 can be written as

                        X divided by 5

Ten subtracted from the quotient of a number and 5 can be written as

                       (X divided by 5)-10

Ten subtracted from the quotient of a number and 5 is 18 can be written as

                       (X divided by 5)-10=18

  By solving the above equation, find ‘X’

                       (X divided by 5) = 18 + 10

                    X/5=28

                       X = 28 x 5 = 140                    

                       

                   

4 0
3 years ago
Solving Inequalities (Will mark as brainliest)
svlad2 [7]

Answer:

1. x ≤ -8

2. y < -8

3. y < -11

4. n > 10

5. n ≤ -2

6. n ≤ 15

7. n ≤ -5

Step-by-step explanation:

Your goal is to get just the variable on one side of the inequality!

For example, take -2y - 4 > 18.

Add 4 to both sides. So... -2y - 4 + (4) > 18 + (4)

Now you get -2y > 22. Since y isn't by itself, let's divide both sides by -2.

So, (-2y / -2) > (22 / -2)

<u>Anytime you're dividing something by a negative, remember to FLIP THE SIGNS.</u> So instead of a greater than, it will now be a less than sign <.

Now you get, y < -11

5 0
2 years ago
A box has 16 candies.12 red and 4 yellow.If you were picking candies from the box without looking.How many candies would you hav
ivolga24 [154]

Answer:

you would have to pick me 4 candies since 12 are red you have a higher chance to get red then you have to get yellow.

7 0
3 years ago
assuming boys and girls are equally likely find the probability of a couple having a baby boy when their third child is born. gi
Sidana [21]

Answer:

After the first 2 children are born, whatever their sex, the chance of having either a boy or a girl is 1/2 or %50. ( Independent event)  

Prior to having any children the chance of having 3 children that are girls is 1/2 x 1/2 x 1/2 = 1/8 or %12.5 ( Dependent event)

Step-by-step explanation:


7 0
4 years ago
Please helppppppp<br><br>give u 10 pts​
Andrew [12]

Answer:

y = x / -4

Step-by-step explanation:

Hope that helps!

8 0
3 years ago
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