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2 years ago

What's the value of x 163=2+69

Mathematics

1 answer:

Nezavi [6.7K]2 years ago

8 0

I got 71 but I’m not quite sure

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95.81 rounded to the nearest whole number

Nady [450]

The nearest whole number would be 96

8 0

2 years ago

Solve the quadractic formula 3x+x-3=0

Mumz [18]

Answer: x = 0.75

Step-by-step explanation:

3x+x - 3 =0

4x - 3=0

4x = 3

x = 0.75

7 0

2 years ago

Read 2 more answers

Alma invests $300 in an account that compounds interest annually. After 2 years, the balance of the account is $329.49. To the n

-Dominant- [34]

Invested amount (P) = $300.

Time in years (t) = 2 years.

Balance after 2 years (A) = $329.49.

Let us assume rate of interest = r % compounds annually.

We know, formula for compound interest

$A=P(1+r)^t$

Plugging values in formula, we get

$329.49=300(1+r)^2$

$\mathrm{Divide\:both\:sides\:by\:}300$

$\frac{300\left(1+r\right)^2}{300}=\frac{329.49}{300}$

$\left(1+r\right)^2=1.0983$

Taking square root on both sides, we get

$1+r=\sqrt{1.0983}$

$\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}$

$1+r-1=\sqrt{1.0983}-1$

$r=\sqrt{1.0983}-1$

$r=1.048-1$

r=0.048.

Converting it into percentage by multiplying by 100.

r=0.048 × 100

r = 4.8 %

Therefore, the rate of interest on the account is 4.8% compounds annually.

5 0

3 years ago

Find the arc measure of AB.<br> The measure of arc AB = ______ degrees

mariarad [96]

The picture is difficult to read, but it looks like
∠ADB = 2x²
∠ACB = 10x
These two angles have equal measure, so you have
2x² = 10x
2x(x -5) = 0 . . . . . subtract 10x and factor
x = 0, or x = 5

The measure of arc AB is twice the measure of either inscribed angle, so would be
arc AB = 2×10x
= 2×10×5
= 100 . . . . . degrees

Arc AB is 100°.

7 0

2 years ago

Evaluate (if possible) the six trigonometric functions of the real number. (If not possible, enter IMPOSSIBLE.)

kotegsom [21]

$\sin(t) = \frac{1}{2} 
\\
\\ \cos(t) = - \frac{ \sqrt{3} }{2} 
\\
\\ \tan(t) = \frac{\sin(t)}{\cos(t)}= - \frac{1}{ \sqrt{3} } 
\\
\\ \csc(t) = \frac{1}{\sin(t)}= 2 
\\
\\ \sec(t) =\frac{1}{\cos(t)}=- \frac{2}{ \sqrt{3}} 
\\
\\ \cot(t) = \frac{1}{\tan(t)}=- \sqrt{3}$

3 0

2 years ago