The two equations would be
32a+50b=14600
10a+40b=7000
To solve, we need to eliminate one variable.... let’s eliminate b
4(32a+50b=14600) —> 128a+200b=58400
-5(10a+40b=7000) —> -50a-200b=-35000
So when we add them together’ we get 78a = 23400
So solve that and a= 300, so class a tickets cost 300 euros each
Substitute a=300 into first equation in the system of equations at the beginning and 32(300)+50b=14600 —> 9600+50b=14600 —> 50b = 5000 or b= 100, so the cost for class b tickets is 100 euros each
To find the change in elevation all you need to do is divide 3 from 1200
Step-by-step explanation:
the answer to this education is -8
<h3>
Answer: Choice D) 56 degrees</h3>
How I got that answer:
Angle DCE is given to be 62 degrees. By the inscribed angle theorem, It doubles to 124 degrees, which is the measure of central angle DAE.
Note how angles DAF and DAE are a linear pair. This means they are adjacent supplementary angles. So they add to 180
(angle DAF)+(angle DAE) = 180
(angle DAF) + (124) = 180
angle DAF = 180-124
angle DAF = 56
