The ratio of change in angular position to change in time is defined as the angular velocity. Thus, the slope of an angular position versus time graph gives the angular velocity of the object being graphed.
The rank of the given graphs can be written as follow,positive graphs are listed first.
The line B is the line with the greater positive slope.
The line B is the line with positive slope but is less than the slope of line B.
The lines A,t ,and F are the lines with the zero slope.
The lines D and E are parallel to each other and have same negative slope.

7 0

3 years ago

A particle moves along the curve below. y = √ 3 + x 3 y=3+x3 As it reaches the point ( 1 , 2 ) (1,2), the y y-coordinate is incr

nydimaria [60]

Answer:

The x-coordinate of the point changing at ¼cm/s

Step-by-step explanation:

Given

y = √(3 + x³)

Point (1,2)

Increment Rate = dy/dt = 3cm/s

To calculate how fast is the x-coordinate of the point changing at that instant?

First, we calculate dy/dx

if y = √(3 + x³)

dy/dx = 3x²/(2√(3 + x³))

At (x,y) = (1,2)

dy/dx = 3(1)²/(2√(3 + 1³))

dy/dx = 3/2√4

dy/dx = 3/(2*2)

dy/dx = ¾

Then we calculate dx/dt

dx/dt = dy/dt ÷ dy/dx

Where dy/dx = ¾ and dy/dt = 3

dx/dt = ¾ ÷ 3

dx/dt = ¾ * ⅓

dx/dt = ¼cm/s

The x-coordinate of the point changing at ¼cm/s

7 0

3 years ago