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2 years ago

Multiply. What is the value of the second partial product? 26 × 107

Mathematics

1 answer:

Reil [10]2 years ago

8 0

Answer:

Below

Step-by-step explanation:

(20*100)+(20*7)+(100*6)+(7*6)

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On a spinner, there are 10 equal spots, numbered 1-10. What is the probability of spinning a 5 and then spinning a 5 again?

inessss [21]

Answer:

1 out of ten

Step-by-step explanation:

so if there are ten sides and all are numbered 1-10 then 5 is only one tenth.

8 0

2 years ago

vaieri [72.5K]

Answer:

see explanation

Step-by-step explanation:

Note the common difference d between consecutive terms of the sequence

8 - 6 = 10 - 8 = 2

This indicates that the sequence is arithmetic with n th term

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 6 and d = 2, thus

$a_{n}$ = 6 + 2(n - 1) = 6 + 2n - 2 = 2n + 4 ← explicit formula

Hence

$a_{130}$ = (2 × 130) + 4 = 260 + 4 = 264

8 0

3 years ago

$4,700 is invested in an account earning 6.2% interest (APR), compounded

pickupchik [31]

Answer:

(5 x (-20)) * (100 x (0.7))

4 0

1 year ago

Your basketball team scored 4 fewer than twice as many points, x, as the other team. a. Write an expression for the number of po

velikii [3]

Answer:

A) p = 2x - 4 for the expression. B) Your team scored 44 points.

Step-by-step explanation:

Let <u>P</u> represent the points your team made.

Since the question says "Your basketball team scored 4 fewer than twice as many points as the other team." this is how I came up with the expression.

p = 2x - 4 ( our points = 2 times more then the other teams points minus 4.

Using this expression and the given information that the other team made 24 points, I solved B.

44 = 2(24) - 4.

3 0

3 years ago

20 people applied for a job. Everyone either has a school certificate or diploma or even both. If 14 have school certificates an

STatiana [176]

Given:

Either has a school certificate or diploma or even both = 20 people

Having school certificates = 14

Having diplomas = 11

To find:

The number of people who have a school certificate only.

Solution:

Let A be the set of people who have school certificates and B be the set of people who have diplomas.

According to the given information, we have

$n(A)=14$

$n(B)=11$

$n(A\cup B)=20$

We know that,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=14+11-n(A\cap B)$

$20=25-n(A\cap B)$

Subtract both sides by 25.

$20-25=-n(A\cap B)$

$-5=-n(A\cap B)$

$5=n(A\cap B)$

We need to find the number of people who have a school certificate only, i.e. $n(A\cap B')$ .

$n(A\cap B')=n(A)-n(A\cap B)$

$n(A\cap B')=14-5$

$n(A\cap B')=9$

Therefore, 9 people have a school certificate only.

3 0

2 years ago