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Iteru [2.4K]
3 years ago
11

Evaluate b - 2a - c for a = -7, b =3, and c = 7 A. 24 B. -18 C. 3 D. 10

Mathematics
2 answers:
MrRa [10]3 years ago
5 0
The answer is D. 10. I hope I helped!
KatRina [158]3 years ago
3 0
B - 2a - c
= 3 - 2*(-7) - 7
= 3 + 14 -7
= 17 -7
= 10

In short, the answer would be D.10.

Hope this helps !

Photon
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Someone please help with parts a b c and d. I will mark brainlest!!!
maria [59]

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6 0
3 years ago
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How do I do this??!.​
ryzh [129]
<h3>  What is trigonometry?</h3>

Trigonometry is the branch of geometry that gives the relationship between the angles and sides of a triangle.

c) proof. if cos∅ = \frac{x}{\sqrt{x^{2} + y^{2}  } }<em>,  </em>then x = adjacent, \sqrt{x^{2} + y^{2} } = hypotenuse

  To solve for opposite, since it is a right angle triangle

   hypotenuse^{2} = opposite^{2} + adjacent^{2}

  (\sqrt{x^{2}  + y^{2} }) ^{2} = opposite^{2} + x^{2}

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xsin∅ = x(\frac{y}{\sqrt{x^{2}  + y^{2} } }) = \frac{xy}{\sqrt{x^{2} } + y^{2}  }

ycos∅ =  \frac{xy}{\sqrt{x^{2} } + y^{2}  }

Therefore xsin∅ = ycos∅

d) 41 sin∅ = 40

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\frac{tan \alpha }{tan^{2}\alpha  - 1 } = 40/9 ÷ (\frac{40}{9} )^{2} - 1 = 40/9  ÷ 1600/81 - 1

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e) 1 - cos ∅ = 1/2

    cos ∅  = 1 - 1/2 = 1/2

   ∅ = cos inverse of 0.5 = 60°

   tan 60 = \sqrt{3}    tan^{2} 60 = 3, sin 60 = \frac{\sqrt{3} }{2} sin^{2} 60 = 3/4

      tan^{2} 60 +  4sin^{2} 60 = 3 + 4(3/4) = 3 + 3 = 6

Learn more about trigonometry: brainly.com/question/24349828

#SPJ1

   

4 0
2 years ago
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