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Stels [109]
3 years ago
11

Simplify the expression. n+ 3(n + 1) = 0​

Mathematics
1 answer:
laila [671]3 years ago
4 0

Answer:

n=-3/4

Step-by-step explanation:

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Problem 1:
vitfil [10]
Melanie pumps 2 in per hr....Lori pumps 4 in per hr
so Lori pumps water at a faster rate

Yolanda writes 1 per day...Zoe writes 2 per day
so Zoe has higher the rate of production


4 0
3 years ago
A certain type of nuts are on sale at $0.35 per pound. Tamara buys 0.2 pound of nuts. How much will the nuts cost? 20 points~!
cupoosta [38]

Answer

$0.07

Step-by-step explanation:

8 0
3 years ago
To mail a package, the rate is x cents for the first pound and y cents for each additional pound, where x>y. Two packages wei
horrorfan [7]

Answer:

Option A) Combined, with a saving of x-y cents      

Step-by-step explanation:

We are given the following in the question:

The rate to mail a package is x cents for first pound and y cents for each additional pound.

x>y

Weights of packages =

3 pounds and 5 pounds

Cost of combined package:

Total weight = 8 pounds

C\text{(combined)} = x + 7y

Cost of sending separately:

C\text{(separated)} = (x + 2y) + (x + 4y) = 2x + 6y

Difference between cost of sending the packages separately and combined

C\text{(separated)}-C\text{(combined)} \\=2x + 6y-(x+7y)\\=(x-y)\text{ cents}

Thus, sending the packages combined is a cheaper method with a saving of (x-y) cents

Thus, the correct answer is:

Option A) Combined, with a saving of (x-y) cents

4 0
4 years ago
joe scored less than four times the amount of baskets peter scored. How many did they each score if l together they scored 32 ba
slava [35]

Let us assume the amount of baskets Joe scored = x baskets.

4 times of x is 4x.

4x+x = 5x.

Therefore, Peter scored = 5x.

Together they scored = 32 baskets.

Sum of Peter score and Joe score = 32.

x+5x = 32.

6x = 32.

Dividing both sides by 6, we get

x = 32/6

= 16/3.

x= 16/3.

<h3>Joe scored = 16/3 baskets.</h3><h3>Peter scored = 5 × 16/3 = 80/3 baskets.</h3>

6 0
3 years ago
The radioactive substance cesium-137 has a half-life of 30 years. The amount A (t)(in grams) of a sample of cesium-137 remaining
lakkis [162]
Rather than use that formula, look at the attachment and use the 4th equation.

Ending Amount = Beginning Amount / 2^n
where "n" is the number of half-lives.  "n" = elapsed time / half-life
(Is 934 the beginning amount? Let's say it is.)

for 40 years, n=40/30 = 1.3333333...
Ending Amount = 934 / 2^1.3333333...
Ending Amount = 934 / <span> <span> <span> 2.5198420998 </span> </span> </span>
Ending Amount = <span> <span> <span> 370.66 grams
</span></span></span>
for 100 years, n=100/30 = <span> <span> <span> 3.333333 </span> </span> </span> ...
Ending Amount = 934 / 2^<span> <span> 3.333333 </span> </span> ...
Ending Amount = 934 / <span> <span> <span> 10.0793683992 </span> </span> </span>
Ending Amount = <span> <span> <span> 92.66 grams

Source:
http://www.1728.org/halflife.htm

</span></span></span>

4 0
3 years ago
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