1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeka57 [31]
4 years ago
13

A weather station in a major city in the Northwest kept data about the weather conditions over the past year. The probabilities

are displayed in the table below:
Hot Mild Cold
Sunny 0.15 0.30 0.10
Cloudy 0.10 0.25 0.10


If a random day is chosen from this data, what is the probability that the day was hot or sunny?
Mathematics
2 answers:
Marat540 [252]4 years ago
7 0

0.15 + 0.1 + 0.3 + 0.1 = 0.65

Black_prince [1.1K]4 years ago
3 0
It is important to note that all the information's required are already given in the question

Probability that a day will be hot = 0.15 + 0.10
                                                   = 0.25
Probability that a day will be sunny = 0.15 + 0.30 + 0.10
                                                        = 0.55
Adding the above two probabilities, we get = 0.25 + 0.55
                                                                     = 0.80
Now
Probability that a day will be both hot and sunny = 0.15
So
Probability that a day was hot or sunny = 0.80 - 0.15
                                                               = 0.65
I hope the procedure is clear enough for you to understand.
You might be interested in
Please help need to turn in almost ! Pic below<br> Thank you so much:)
11111nata11111 [884]

Answer:

x = 90-73

= 17°

.................

4 0
3 years ago
Read 2 more answers
4.23<br> +6.51<br> ??????????
Anvisha [2.4K]

Answer:

10.74

Step-by-step explanation:

add both digits in each column

8 0
4 years ago
Read 2 more answers
....sigh....<br> Shout out to Taater for being helpful in times of need :3
Ne4ueva [31]

Answer:

Taater is a good friend of mine.

Step-by-step explanation:

The answer would be the third option, hope I'm just as helpful in times of need if its possible to subtract those then it's 100% the first option. Sorry don't exactly know this, so I'm at least trying to help.

3 0
3 years ago
Reflect triangle a in the line y = 1
alekssr [168]

Answer:

y is one x is two and line y is 1

8 0
3 years ago
Read 2 more answers
The number of defective circuit boards coming off a soldering machine follows a Poisson distribution. During a specific ten-hour
Alexus [3.1K]

Answer:

a) the probability that the defective board was produced during the first hour of operation is \frac{1}{10} or 0.1000

b) the probability that the defective board was produced during the  last hour of operation is \frac{1}{10} or 0.1000

c) the required probability is 0.2000

Step-by-step explanation:

Given the data in the question;

During a specific ten-hour period, one defective circuit board was found.

Lets X represent the number of defective circuit boards coming out of the machine , following Poisson distribution on a particular 10-hours workday which one defective board was found.

Also let Y represent the event of producing one defective circuit board, Y is uniformly distributed over ( 0, 10 ) intervals.

f(y) = \left \{ {{\frac{1}{b-a} }\\\ }} \right   _0;   ( a ≤ y ≤ b )_{elsewhere

= \left \{ {{\frac{1}{10-0} }\\\ }} \right   _0;   ( 0 ≤ y ≤ 10 )_{elsewhere

f(y) = \left \{ {{\frac{1}{10} }\\\ }} \right   _0;   ( 0 ≤ y ≤ 10 )_{elsewhere

Now,

a) the probability that it was produced during the first hour of operation during that period;

P( Y < 1 )   =   \int\limits^1_0 {f(y)} \, dy

we substitute

=    \int\limits^1_0 {\frac{1}{10} } \, dy

= \frac{1}{10} [y]^1_0

= \frac{1}{10} [ 1 - 0 ]

= \frac{1}{10} or 0.1000

Therefore, the probability that the defective board was produced during the first hour of operation is \frac{1}{10} or 0.1000

b) The probability that it was produced during the last hour of operation during that period.

P( Y > 9 ) =    \int\limits^{10}_9 {f(y)} \, dy

we substitute

=    \int\limits^{10}_9 {\frac{1}{10} } \, dy

= \frac{1}{10} [y]^{10}_9

= \frac{1}{10} [ 10 - 9 ]

= \frac{1}{10} or 0.1000

Therefore, the probability that the defective board was produced during the  last hour of operation is \frac{1}{10} or 0.1000

c)

no defective circuit boards were produced during the first five hours of operation.

probability that the defective board was manufactured during the sixth hour will be;

P( 5 < Y < 6 | Y > 5 ) = P[ ( 5 < Y < 6 ) ∩ ( Y > 5 ) ] / P( Y > 5 )

= P( 5 < Y < 6 ) / P( Y > 5 )

we substitute

 = (\int\limits^{6}_5 {\frac{1}{10} } \, dy) / (\int\limits^{10}_5 {\frac{1}{10} } \, dy)

= (\frac{1}{10} [y]^{6}_5) / (\frac{1}{10} [y]^{10}_5)

= ( 6-5 ) / ( 10 - 5 )

= 0.2000

Therefore, the required probability is 0.2000

4 0
3 years ago
Other questions:
  • HELP PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ!!!
    11·2 answers
  • Hattie is making fruit baskets, which includes apples and bananas, to send to some of her real estate clients. She wants each ba
    5·2 answers
  • Considering only functions with a greater rate of change than that of the function represented on the graph, which function has
    9·1 answer
  • What is the answer to this question. 3x-4&lt;-24
    13·1 answer
  • Find the area of a rectangle whose side lengths are 4x² and 6x²– 3x.
    14·2 answers
  • The endpoints of a line segment are G(1,7) and H(-3,11). Find the coordinates of the midpoint M.
    10·1 answer
  • [NEED ANSWERED, ASAP, 15 POINTS AND BRAINILEST IF WELL EXPLAINED]
    15·1 answer
  • PLEASE HELP MEEEE!!!!! Marcos had 15 coins in nickels and quarters total amount of those coins is $2.25. How many quarters and d
    12·1 answer
  • Hey! Can someone please help me with this question? Really appreciate it
    13·1 answer
  • 1 • x=3 what is the property
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!