Using the law os cosines formula b^2 = a^2 + c^2 - 2*a*c*cos(B)
a = 17, b = 8, c = 16
8^2 = 17^2 + 16^2 - 2*17*16* cos(B)
64 = 289 + 256 - 544 * cos(B)
544*cos(B) = 289 + 256 - 64
544 * cos(B) = 481
cos (B) = 481/544
B = arccos(481/544)
B = 27.8 degrees
Answer:
dy=9-y
dx=x
Step-by-step explanation:
Answer:
The distance between point M and point L is 8
Step-by-step explanation:
The given points on the coordinate are M = (- 2, 4) and L = (4, - 1)
The formula for determining the distance between two points is expressed as
d = √(x2 - x1)^2 + (y2 - y1)^2
Where
y2 = final value of y = - 1
y1 = initial value of y = 4
x2 = final value of x = 4
x1 = initial value of x = - 2
Therefore,
d = √(4 - - 2)^2 + (- 1 - 4)^2
d = √6^2 + (-5)^2
d = √36 + 25
d = √61 = 8
Hi there!
In order to solve this problem, we should first write this into expressions.
Let x = the bigger number
Let y = the smaller number
x + y = 37
x = 3y + 5
Now, we can use substitution of the system ofinequalities to solve.
We substitute the value of x into the equation.
3y + 5 + y = 37
Now, we simplify.
4y + 5 = 37
4y = 32
y = 8
So, 8 is the answer.
Hope this helps!
