All categories

3 years ago

M Give one reason why banks charge people banking fees.

Mathematics

1 answer:

stepan [7]3 years ago

7 0

Answer:

banks change people fees to make a profit off of them other wise they would be giving away free money.

Step-by-step explanation:

hope this helps and what you were asking for.

You might be interested in

Where does the pythagorean identity sin^2 + cos^2=1 come from? How does it relate to right triangles?

Arada [10]

Consider a right triangle with hypotenuse of 1.
sin x means to divide the side in front of the angle by hypotenuse
cos x means to divide the side beside the angle by hypotenuse
we know that a^2+b^2=c^2 now divide two sides by c^2
$\frac{ a^{2} }{ c^{2} }+ \frac{ b^{2} }{ c^{2} }=1$
c is 1 also a/c means sinx and b/c is cos x so
sin^2(x)+cos^2(x)=1

8 0

4 years ago

3y''-6y'+6y=e*x sexcx

Simora [160]

From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

$3r^2-6r+6=0\iff r^2-2r+2=0$

which has roots at $r=1\pm i$ . This admits the two fundamental solutions

$y_1=e^x\cos x$
$y_2=e^x\sin x$

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

$y_p=u_1y_1+u_2y_2$

where

$u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx$

and $W(y_1,y_2)$ is the Wronskian of the fundamental solutions. We have

$W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}$

and so

$u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx$
$u_1=\dfrac13\ln|\cos x|$

$u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx$
$u_2=\dfrac13x$

Therefore the particular solution is

$y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

so that the general solution to the ODE is

$y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x$

7 0

3 years ago

Factor the expression 2x^3-10x^2-5x+25. Show your work.

azamat

Step 1. Factor out common terms in the first two terms, then in the last two terms.

2x^2(x - 5) -5(x - 5)

Step 2. Factor out the common term x - 5

(x - 5)(2x^2 - 5)

4 0

3 years ago

What is the value of X? A.10 B.7 C.11 D.4

Zinaida [17]

Answer:

the answer is c

Step-by-step explanation:

just guess lol

6 0

3 years ago

Please help and please say the formula!!

Damm [24]

Answer:

Step-by-step explanation:

Formula: 4*((15*7)/2) + 15^2

This is the area of the four triangles combined (210 cm^2) plus the area of the square (225 cm^2)

8 0

3 years ago