3 years ago

Select all equations that are true

Mathematics

1 answer:

Serhud [2]3 years ago

5 0

B, C, D i had to simplify some! please mark me brainliest?

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the amount of radioactive isotope decays in half every year. the amount of isotope can be modeled f(x)=346(1/2)^x and f(1)=173.

max2010maxim [7]

The 346 is the original mass of the radioactive isotope.

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3 years ago

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Katelyn did a survey of 200 randomly selected gym members, and found that 72 of them are interested in yoga classes. The gym has

Georgia [21]

Answer:

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360 members

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3 years ago

If x+1/x= 3, then prove that m^5+1/m^5= 123

alina1380 [7]

9514 1404 393

Explanation:

We can start with the relations ...

$\displaystyle\left(x+\frac{1}{x}\right)^3=\left(x^3+\frac{1}{x^3}\right)+3\left(x+\frac{1}{x}\right)\\\\\left(x+\frac{1}{x}\right)^5=\left(x^5+\frac{1}{x^5}\right)+5\left(x^3+\frac{1}{x^3}\right)+10\left(x+\frac{1}{x}\right)\\\\\textsf{From these, we can derive ...}\\\\x^5+\frac{1}{x^5}=\left(x+\frac{1}{x}\right)^5-5\left(\left(x+\frac{1}{x}\right)^3-3\left(x+\frac{1}{x}\right)\right)-10\left(x+\frac{1}{x}\right)$

$\displaystyle x^5+\frac{1}{x^5}=\left(x+\frac{1}{x}\right)^5-5\left(x+\frac{1}{x}\right)^3+5\left(x+\frac{1}{x}\right)\right)\\\\x^5+\frac{1}{x^5}=3^5 -5(3^3)+5(3)\\\\=((3^2-5)3^2+5)\cdot3=(4\cdot9+5)\cdot3=(41)(3)\\\\=\boxed{123}$