Using Lagrange multipliers, we have the Lagrangian

with partial derivatives (set equal to 0)




Substituting the first three equations into the fourth allows us to solve for

:

For each possible value of

, we get two corresponding critical points at

.
At these points, respectively, we get a maximum value of

and a minimum value of

.
Answer:
can't really do that.
Step-by-step explanation:
whats the numbers lol
Answer:
b = 10
Step-by-step explanation:
The area (A) of a triangle is calculated as
A =
bh ( b is the base and h the height )
Here h = 3x + 15 and A = 15x + 75, thus
× b × (3x + 15) = 15x + 75
Multiply both sides by 2 to clear the fraction
b(3x + 15) = 30x + 150
Divide both sides by (3x + 15)
b =
← factor numerator and denominator
=
← cancel the factor (x + 5) on numerator/denominator
= 
= 10
D(1,-5,-4,-7) R(0,7,-7,-4) Domain are your x values and range is your y values