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Serjik [45]
3 years ago
10

HELP ME 20 POINTS + BRAINLEST GIVE ME THE CORRECT ANSWER

Mathematics
1 answer:
zavuch27 [327]3 years ago
4 0

Answer:

unit rate:2 y-intercept:6

Step-by-step explanation:

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What is the slope of the line that contains these points?
Setler79 [48]

Answer:

what are the 2 points? please write your points as (x, y).

4 0
3 years ago
Helpp ill mark u as brain list​
kirill [66]

Answer:

16.C

17.20

Step-by-step explanation:

16.Add 8+5=13

17.Add 12+8=20

7 0
2 years ago
Find the length of the mid segment the diagram is not to scale
zepelin [54]
Using the left or right side of triangle, you can conclude that the midsegment will divide the triangle in both midlines of the sides. This means the length of the line would be half of the line below it. The equation would be:

47/4x+2= 94/ 4x+44
4x+44/ 4x+2 = 94/47
4x+ 44 / 4x+2  =2
4x+44  = 2(4x+2)
4x+44 = 8x+4
 4x-8x= 4-44
-4x= -40
x= 10

Then the length of midline would be:
4x+2= 4(10)+2= 42
4 0
3 years ago
Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at B
Galina-37 [17]

Answer:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

8 0
3 years ago
Find the values of m and n that make equation true. <br><br> 8+15i=2m+3ni
Brilliant_brown [7]

gthy67jntgrt67u89i7yu holfcedikjnhfnhtfrolwsfr n/lkjhfwr3n oljfu vikr8hneikoeOPDTE85417

+TE4TE

8 0
3 years ago
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