Answer:
i dont really know
Step-by-step explanation:
i am doing this for the point things
Answer:
D.(2, 2)
Step-by-step explanation:
- Staring point = (2, -4)
- Since he moved 6 units up, so, there will be change in only y-coordinate of the starting point and x-coordinate will remain unchanged.
- End point of the segment = (2, - 4 + 6) = (2, 2)
A point (-0.8, 0.6) will be a point on the unit circle in the second quadrant. Since it is a unit circle, its radius is 1, and we have
sin(α) = y = 0.6
cos(α) = x = -0.8
tan(α) = y/x = 0.6/-0.8 = -0.75
The angle is α = arccos(-0.8) ≈ 143.13°
______
For the unit circle, the trig values are always the coordinates or their ratio as shown above, regardless of quadrant.
Answer:
B) 29
Step-by-step explanation:
Given:
AC= 58
Point D and E are the midpoints of side AB and BC Respectively.
Solution:
According to Midpoint theorem which states:
"The segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side."
DE=
AC
DE= ![\frac{58}{2} =29](https://tex.z-dn.net/?f=%5Cfrac%7B58%7D%7B2%7D%20%3D29)
Hence length of DE is 29.