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2 years ago

Determine whether each set of data can be modeled by an exponential function. If so, find the exponential

Mathematics

1 answer:

Sergeeva-Olga [200]2 years ago

3 0

It can be modeled by an exponential function, f(x) is divided by 3 each time x increases by 1.

This means that the base of the exponential function is 1/3, and since the value of f(x) when x=0 is 81, $f(x)=81\left(\frac{1}{3} \right)^{x}$

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What is the y coordinate of the point that divides the

svet-max [94.6K]

Answer:

the y coordinate is 5

Step-by-step explanation:

In the figure attached, the directed line segment is shown.

J is located at (-3, 1) and K is located at (-8, 11)

run: x2 -x1 = -8 - (-3) = -5

rise: y2 - y1 = 11 - 1 = 10

Taking J as reference, the coordinate of the point that divides the directed line segment from J to k into a ratio of 2:3 is:

c = 2/(2+3) = 0.4

(x1 + c*run, y1 + c*rise)

(-3 + 0.4*-5, 1+0.4*10)

(-5, 5)

6 0

3 years ago

Please help me with these, oh sweet jesus

Lelechka [254]

Answer:

77. $\cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} x$ Proved

78. $\sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ]$ Proved

79. $\cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x$ Proved.

80. $\sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x$ Proved.

Step-by-step explanation:

77. Left hand side

= $\cot^{6} x$

= $\cot^{4} x \times \cot^{2} x$

= $\cot^{4}x [\csc^{2}x - 1]$

{Since we know, $\csc^{2} x - \cot^{2}x = 1$ }

= $\cot^{4} x \csc^{2}x - \cot^{4} x$

= Right hand side (Proved)

78. Left hand side

= $\sec^{4}x \tan^{2} x$

= $\sec^{2} x [1 + \tan^{2}x] \tan^{2} x$

{Since $\sec^{2}x - \tan^{2}x = 1$ }

= $\sec^{2}x [\tan^{2}x + \tan^{4}x ]$

= Right hand side (Proved)

79. Left hand side

= $\cos^{3} x\sin^{2} x$

= $\cos x[1 - \sin^{2} x] \sin^{2} x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $[\sin^{2}x - \sin^{4}x] \cos x$

= Right hand side

80. Left hand side

= $\sin^{4}x - \cos^{4}x$

= $[\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x$

{Since $\sin^{2}x + \cos^{2} x = 1$ }

= $1 - 2\cos^{2} x[1 - \cos^{2}x ]$

= $1 - 2\cos^{2}x + 2 \cos^{4} x$

= Right hand side. (Proved)

7 0

3 years ago

Factor this polynomial.<br> .-2x2 - 7x-3

lapo4ka [179]

Answer:

Its B

Step-by-step explanation:

Mark as Brainllest!!

8 0

3 years ago

Divide -1.53 ÷ 0.17 enter your answer in the box PLEASE HELLPPP

marshall27 [118]

Answer:

-9

Step-by-step explanation:

-1.53 ÷ 0.17 =‬ -9

check work:

-9 x 0.17 = -1.53

6 0

3 years ago

Read 2 more answers

Write 10 places in India and write their population in Indian and international system

gulaghasi [49]

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Solution :-

Following are the population of five major cities of India according to the Census of 2011.

1) Mumbai

a) Indian System :

1,24,42,373 - One Crore Twenty Four Lakh Forty Two Thousand Three Hundred Seventy Three.

b) International system :

12,442,373 - Twelve Million Four Hundred Forty Two Thousand Three Hundred Seventy Three.

2) Delhi

a) Indian System :

1,10,34,555 - One Crore Ten Lakh Thirty Four Thousand Five Hundred Fifty Five.

b) International System :

11,034,555 - Eleven Million Thirty Four Thousand Five Hundred Fifty Five.

3) Bangalore

a) Indian System :

84,43,675 - Eighty Four Lakh Forty Three Thousand Six Hundred Seventy Five.

b) International system :

8,443,675 - Eight Million Four Hundred Forty Three Thousand Six Hundred Seventy Five.

4) Hyderabad

a) Indian System :

67,31,790 - Sixty Seven Lakh Thirty One Thousand Seven Hundred Ninety.

b) International System :

6,731,790 - Six Million Seven Hundred Thirty One Thousand Seven Hundred Ninety.

5) Ahmedabad

a) Indian System :

55,77,940 - Fifty Five Lakh Seventy Seven Thousand Nine Hundred Forty.

b) International System :

5,577,940 - Five Million Five Hundred Seventy Seven Thousand Nine Hundred Forty.

5 0

2 years ago

Read 2 more answers