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hichkok12 [17]
2 years ago
10

Ill mark branlist plls help

Mathematics
1 answer:
Leona [35]2 years ago
6 0
It looks at about 48. Hard to tell tho
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A triangle with vertices A(0,0), B(6,0), and C(0,9) is rotated 360 about the y-axis. What is the volume of the figure?
Luden [163]

Given:

A triangle with vertices A(0,0), B(6,0), and C(0,9) is rotated 360 about the y-axis.

To find:

The volume of the figure.

Solution:

Points A(0,0) and C(0,9) lies on the y-axis. Length of AC is 9 units.

Points A(0,0) and B(6,0) lies on the x-axis. Length of AB is 6 units.

If a triangle with vertices A(0,0), B(6,0), and C(0,9) is rotated 360 about the y-axis, then it will form a cone with radius 6 units and height 9 units.

Volume of a cone is

V=\dfrac{1}{3}\pi r^2h

where, r is radius of the base and h is vertical height of the cone.

Putting r=6 and h=9, we get

V=\dfrac{1}{3}\pi (6)^2(9)

V=\pi (36)(3)

V=108\pi

Therefore, the volume of the figure is 108\pi sq. units.

7 0
3 years ago
Help with math homework
aliya0001 [1]
You just divide. 38÷12=3.166~ $3.17
4 0
3 years ago
Use trigonometric identities to solve each equation within the given domain.
saul85 [17]
Do you need help or you just wanted the answers
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3 years ago
Tan^2x+sec^2x=1 for all values of x. <br> true or false?
amid [387]

This is not true.

\tan^2x+\sec^2x=\dfrac{\sin^2x}{\cos^2x}+\dfrac1{\cos^2x}=\dfrac{1-\cos^2x+1}{\cos^2x}=2\sec^2x-1

2\sec^2x-1=1\implies\sec^2x=1\implies\sec x=\pm1\implies x=n\pi

where is n is any integer. So suppose we pick some value of x other than these, say x=\dfrac\pi4. Then

\tan^2\dfrac\pi4+\sec^2\dfrac\pi4=1+2=3\neq1

5 0
3 years ago
Read 2 more answers
GRAPHING INEQUALITIES
Rudiy27
I don’t know put 2x on the x axis and dot 0 on the y axis
6 0
3 years ago
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