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3 years ago

0.5% of what number is 5

Mathematics

2 answers:

Salsk061 [2.6K]3 years ago

8 0

Answer:1000...I think

Step-by-step explanation: 0.5 can go into 100, 200 times 5 times 200=1000

Otrada [13]3 years ago

4 0

Answer:

1,000

Step-by-step explanation:

5/10ths of a percent of what number is 5-which would be 1000

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Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

3 years ago

Yearly tuition, housing, and fees for a local college are $10,500, $1300, and $2170 respectively. You have saved $3100 and have

Natalija [7]

Answer:

4,370

Step-by-step explanation:

add 10,500, 1,300, and 2,170

then add 3,100 and 6,500

subtract both sums

got it

4 0

3 years ago

The sum of two numbers is 150 the ratio of the same number is 3:2 find the bigger number

Paladinen [302]

$3x-\ bigger\ number\\
2x-\ smaller\ number\\\\
3x+2x=150\\\\
5x=150\ \ \ | divide\ by\ 5\\\\
x=30\\\\
3x=3*30=90\\\\ Bigger\ number\ is\ 90.$

5 0

3 years ago

Cody is cooking pancakes. The recipe calls for 5 3/10 cups of flour. He accidentally put in 8 1/4 cups. How many extra cups did

Eddi Din [679]

Answer:

59/20 cups

Step-by-step explanation:

5 3/10

8 1/4

Common denimainator is 40

5 3/10 = 5 12/40

8 1/4 = 8 10/40

Now we can subtract:

330/40-212/40=118/40

118/40= 59/20 cups

Sorry if I spelled some words wrong

3 0

3 years ago

Many bank accounts never go below zero. But some banks will allow a negative balance, at least for a short time, called an overd

Sergio039 [100]

Answer:

the amount after 3 weeks is $37.33

Step-by-step explanation:

Given that

His balance is -$48.82 i.e. overdraft

Now in order to get the positive balance, he plans to deposit the money of $28.55 per week

We need to find out the amount after 3 weeks

So,

= -$48.32 + $28.55 + $28.55 + $28.55

= $37.33

hence, the amount after 3 weeks is $37.33

3 0

3 years ago