Answer:
The slope intercept of the given line equation AB is ![y = \frac{1}{2} ( x)- \frac{5}{2}](https://tex.z-dn.net/?f=y%20%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%20%28%20x%29-%20%5Cfrac%7B5%7D%7B2%7D)
Step-by-step explanation:
Here,the two given point s are A ( -9,-2) and B (1,3).
Now, the slope m of the line AB = ![= \frac{y_2 - y_1}{x_2 -x_1}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7By_2%20-%20y_1%7D%7Bx_2%20-x_1%7D)
![\implies m = \frac{3 - (-2)}{1 - (-9)} = \frac{3+2}{1+9} = \frac{5}{10} = \frac{1}{2}](https://tex.z-dn.net/?f=%5Cimplies%20m%20%3D%20%5Cfrac%7B3%20-%20%28-2%29%7D%7B1%20-%20%28-9%29%7D%20%20%3D%20%5Cfrac%7B3%2B2%7D%7B1%2B9%7D%20%20%3D%20%5Cfrac%7B5%7D%7B10%7D%20%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
or, the slope of line AB = 1/2
Now, the POINT SLOPE FORM of any equation with point (x0,y0) and slope m is given as :
y - y0 = m (x -x0)
So, the line equation of AB is given as :
![y - 3 = \frac{1}{2} ( x-1)\\\implies y =3 + \frac{1}{2} ( x-1)\\or, y = \frac{1}{2} ( x)- \frac{5}{2}](https://tex.z-dn.net/?f=y%20-%203%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%20%28%20x-1%29%5C%5C%5Cimplies%20y%20%20%3D3%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%28%20x-1%29%5C%5Cor%2C%20y%20%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%20%28%20x%29-%20%5Cfrac%7B5%7D%7B2%7D)
SLOPE INTERCEPT form is y = mx + c
Hence, the slope intercept of the given line equation AB is ![y = \frac{1}{2} ( x)- \frac{5}{2}](https://tex.z-dn.net/?f=y%20%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%20%28%20x%29-%20%5Cfrac%7B5%7D%7B2%7D)
Well I don't know.
Let's you and me get together and figure it out.
You said that . . . . . . . . . . . . . . 3t + 19 = 6
Subtract 19 from each side . . . 3t = -13
Divide each side by 3 . . . . . . . t = -13/3
Did I go too fast for you ?
Answer:Monomial, polynomial, binomial, trinomial, and multinomial.
Step-by-step explanation:
Answer:
45°
Step-by-step explanation:
I assume you meant 45°, not 45%.
90-45=45
If it is actually 45%, then the answer would be:
90x.55=49.5°