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SVETLANKA909090 [29]
3 years ago
5

Sooo Help please I'm Not smart lol<33

Mathematics
2 answers:
svetoff [14.1K]3 years ago
4 0

Answer:

Available answer choices:

-3.891

-3.89

Step-by-step explanation:

This is the sum rounded to the nearest  hundredth and thousandth

Also.. Does the answer need to be entered as a decimal or a fraction?

the answers I gave you might be wrong

Oksana_A [137]3 years ago
3 0
Each hiker will receive 6 ounces each.
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I'm really confused, can you please help me
Anika [276]

Answer: y=8

Step-by-step explanation:

Since DF is bisected, it means but in half. This means DU and UF are equal in length. We can set them equal to each other to find y.

2y=16          [divide both sides by 2]

y=8

4 0
3 years ago
Read 2 more answers
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks.
olasank [31]

Answer:

x=18 y=69

Step-by-step explanation:

3x+5y=399

x+5y=363

2x=36

x=18

18+5y=363

5y=345

y=69

5 0
2 years ago
A student runs 35 m east and then 12 m west. What is the distance run by the
ValentinkaMS [17]

Answer:

A.47 m

Step-by-step explanation:

you a add 35 m east and 12 m west

5 0
3 years ago
Read 2 more answers
Write a proportion that could be used to solve for each variable. Then solve.
iren [92.7K]
60/25 = 12/Y
cross multiply and divide

25 x 12 = 300 

300 / 60 = 5

Y = 5 boxes
4 0
3 years ago
Using a directrix of y = −2 and a focus of (1, 6), what quadratic function is created? Question 3 options:
deff fn [24]

If your directrix is a "y=" line, that means that the parabola opens either upwards or downwards (as opposed to the left or the right). Because it is in the character of a parabola to "hug" the focus, our parabola opens upwards. The vertex of a parabola sits exactly halfway between the directrix and the focus. Since our directrix is at y = -2 and the focus is at (1, 6) AND the parabola opens upward, the vertex is going to sit on the main transversal, which is also the "line" the focus sits on. The focus is on the line x = 1, so the vertex will also have that x coordinate. Halfway between the y points of the directrix and the focus, -2 and 6, respectively, is the y value of 2. So the vertex sits at (1, 2). The formula for this type of parabola is (x-h)^2=4p(y-k) where h and k are the coordinates of the vertex and p is the DISTANCE that the focus is from the vertex. Our focus is 4 units from the vertex, so p = 4. Filling in our h, k, and p: (x-1)^2=4(4)(y-2). Simplifying a bit gives us (x-1)^2=16(y-2). We can begin to isolate the y by dividing both sides by 16 to get \frac{1}{16}(x-1)^2=y-2. Then we can add 2 to both sides to get the final equation f(x)=\frac{1}{16}(x-1)^2+2, choice 4 from above.

7 0
3 years ago
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