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denis-greek [22]
2 years ago
12

What is the slope of the line passing through the points (-1, – 7) and (-9, - 2)?

Mathematics
1 answer:
dimaraw [331]2 years ago
6 0
<h2><u>SLOPE</u></h2>

<h3>\color{darkblue}\mathbb{QUESTION:}</h3>

» What is the slope of the line passing through the points (-1, – 7) and (-9, - 2)?

<h3>\color{brown} \mathbb{ANSWER:}</h3>
  • \color{hotpink} \bold{(Slope) \: m =  - \frac{5}{8}  }

  • \sf \:As \:  a  \: decimal:  \color{hotpink} \bold{ \: m = - 0.625  }

— — — — — — — — — —

<h3>\color{darkblue} \mathbb{FORMULA:}</h3>
  • \tt \:  \underline{  \boxed{ \tt m =  \frac{ y_{2} -  y_{1}}{x_{2} -  x_{1}}}}  \\

<h3>\color{darkblue}\mathbb{GIVEN:}</h3>
  • x_{ 1} =  - 1\: \:   \:  \:  \:  \:  \:  y_{1} =  - 7  \\   x_{2} =  - 9 \:   \:  \:  \:  \: \:  \:  y_{2} =  - 2

<h3>\color{darkblue} \mathbb{SOLUTION:}</h3>
  • \tt m =  \frac{ y_{2} -  y_{1}}{x_{2} -  x_{1}} \\

  • \tt m =  \frac{ ( - 2) -  ( - 7)}{( - 9) -  ( - 1)} \\

  • \tt m =  \frac{  \: 5}{ - 8 \: } \\

  • \tt m =  \underline{ \boxed{  \bold{ - \frac{  5}{  8 } }}} \\

  • \tt m =     \underline{ \boxed{\bold{ - 0.625}}}

_______________❦︎_______________

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What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16
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Answer:

y=\pm i \sqrt{7}

Step-by-step explanation:

Given equation is \frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

Factor denominators then solve by making denominators equal

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

y\left(y+4\right)-4\left(y-4\right)=9

y^2+4y-4y+16=9

y^2=9-16

y^2=-7

take squar root of both sides

y=\pm \sqrt{-7}

y=\pm i \sqrt{7}

Hence final answer is y=\pm i \sqrt{7}.

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The second equation is <span>-5-2y=2, then
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<span>-2y=2-(-5),
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x=33.5÷2,
x=16.75.
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