Answer:
string = input()
normal = ""
reverse = ""
for i in range(len(string)):
if string[i].isalpha():
normal += string[i].lower()
reverse = string[i].lower() + reverse
if normal == reverse:
print(string + " is a palindrome")
else:
print(string + " is not a palindrome")
Explanation:
- Loop up to the length of string.
- Use an if statement to check if a certain character is an alphabet.
- Check if both the normal and reverse strings are equal, then display that it is a palindrome.
Answer:
7
Explanation:
class width=(largest value-smallest value)/k
where k is the number of classes.
According to 2^k>n rule
We choose different value of k till we get the 2^k greater than number of observation.
The given value of n=60
Now,
2^1=2 <60
2^2=4 <60
2^3=8 <60
2^4=16 <60
2^5=32 <60
2^6=64 >60
So, k=6.
Now class width=(largest value-smallest value)/k
class width=72-30/6
class width=42/6=7
class width=7
Answer:
before update
Explanation:
because the update has been made but not submited
Answer:
below
Explanation:
this statement is false because different business have different information needs
The compression ratio is 20:1 please mark me brainliest
