Answer:
D) 14 seconds
Step-by-step explanation:
First we will plug 500 in for y:
500 = -4.9t² + 120t
We want to set this equal to 0 in order to solve it; to do this, subtract 500 from each side:
500-500 = -4.9t² + 120t - 500
0 = -4.9t²+120t-500
Our values for a, b and c are:
a = -4.9; b = 120; c = -500
We will use the quadratic formula to solve this. This will give us the two times that the object is at exactly 500 meters. The difference between these two times will tell us when the object is at or above 500 meters.
The quadratic formula is:
Using our values for a, b and c,
The two times the object is at exactly 500 meters above the ground are at 5 seconds and 19 seconds. This means the amount of time it is at or above 500 meters is
19-5 = 14 seconds.
B - Since it is a dotted inequality, it would be a equal to and something else. And since it is greater than 3, it would be X is equal to or less than 3
Answer:
what the rest of the problem?
Step-by-step explanation:
Answer:
The answer is below
Step-by-step explanation:
Let x represent the number of days that fluffy eats wet food in a week and y represents the number of days that fluffy eats dry food in a week.
Hence:
x + y = 7 (1)
Also, John wants to spend at most $9.00 on cat food each week. Hence:
1.5x + 0.75y ≤ 9 (2)
The list of possible points after solving graphically are:
(0,7), (6,0), (0,12) and (5, 2). If x,y > 0, then the point that satisfies the inequality is:
(5, 2) i.e. 5 wet food and 2 dry food
I'll use multiples of 2 and 4 as an example:
Multiples of 2: 2, 4, 6, 8...
Multiples of 4: 4, 8, 12, 16...
The least common multiple in this case is 4. The LCM is always ≥ the largest starting number, which is 4 for this example. Therefore, the statement is true.
<em>Hope this helps! :)</em>
