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3 years ago

Answer this question to get marked as barinliest!!!!!

Mathematics

1 answer:

kap26 [50]3 years ago

6 0

Here’s the answer and working out. Hope it helps

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Studies on a machine that molds plastic water pipe indicate that when it is injecting 1-inch diameter pipe, the process standard

Tpy6a [65]

Answer is i think
<span>0.67 for you diana</span>

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3 years ago

Help me please 25 points.

sveticcg [70]

The answer i got is VP<------------->

AKA the first option

i hope this is right

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3 years ago

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Find the value of the second term in this sequence. 34, ____ , 84, 109, 134

prohojiy [21]

D = 109 - 84 = 134 - 109 = 25
2nd term = 34 + 25 = 59

8 0

3 years ago

A number added to one third of itself equals 12 . what is the number

Drupady [299]

Answer:

Step-by-step explanation:

x+1/3x=12

(3x+1x)/3=12

4x/3=12

4x=12×3

4x=36

x=36/4

x=9

8 0

2 years ago

Read 2 more answers

A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.

scZoUnD [109]

Answer: The required ratio will be

$84:1034$

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

$2x=30\\\\x=\frac{30}{2}=15\ inches$

So, Length of AD becomes

$3x=3\times 15=45\ inches$

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

$\frac{30}{2}=15\ inches$

So, Area of semicircle along AB and CD is given by

$2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2$

Radius of semicircle along AD is given by

$\frac{45}{2}=22.5\ inches$

Area of semicircle along AD and BC is given by

$2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2$

And the combined area of the semicircles is given by

$\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2$

Area of rectangle is given by

$Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2$

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

$1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034$

Hence, the required ratio will be

$84:1034$

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3 years ago