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2 years ago

A piece of wood is 1212 feet long, and a nail is 33 inches long. The piece of wood is how many times as long as the nail?

Mathematics

1 answer:

qaws [65]2 years ago

6 0

36.7272727272727. I hope this helps.

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Does it matter which dimensions you select for the lenght and the width when you find the area of a rectangle? Explain

Levart [38]

It does not. So Long as the length is multipled by the height aka Long edge multiplied with the short edge, you will obtain the area of the rectangle.

3 0

3 years ago

12+9/3^2 how u do this ?

vredina [299]

3^2 = 9

9/9 = 1

1 + 12 = 13

This is based on the Order of Operations.

Hope it helps! :D

6 0

3 years ago

Read 2 more answers

An apple has a mass of 150g and a volume of 100cm cubed find its density

BartSMP [9]

Divide <span>150:100 to find out what the density in g/cm3 is. So 150:100 = 1.5 g/cm3</span>

8 0

2 years ago

Kelly has a ribbon that is 60 inches long she cuts at 40% of ribbon for an art project while working on the project she decided

Amiraneli [1.4K]

Answer:

8.4 inches

Step-by-step explanation:

To find the amount of inches, multiply the length by the percent. A percent is 40% but can also be written as a decimal conversion as 0.4. Then 40% of 60 inches is 0.4(60)= 24 inches.

However, she didn't use all 24 inches. She used 35%. This converts to 0.35 and then multiply for 0.35(24) = 8.4 inches.

She used 8.4 inches.

4 0

3 years ago

Assume that the following data were generated using a valid and appropriate methodology. XYZ Data Analytics, Inc. Received prope

Hitman42 [59]

Using the z-distribution, as we are working with a proportion, the 95% confidence interval for the proportion of consumers who would buy the product at it's proposed price is (0.3016, 0.3830).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

179 out of 523 members indicated they would buy the new product at the proposed price, hence:

$\pi = \frac{179}{523} = 0.3423$

Then the bounds of the interval are found as follows:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 - 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3016$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3423 + 1.96\sqrt{\frac{0.3423(0.6577)}{523}} = 0.3830$

More can be learned about the z-distribution at brainly.com/question/25890103

4 0

1 year ago