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Nitella [24]
3 years ago
10

PLEASE HELP ITS DUE IN 10 MIN U GET POINTS

Mathematics
2 answers:
Harman [31]3 years ago
7 0

Answer:

50°

Step-by-step explanation:

In parallelogram ABCD,

AB is parallel to CD

angle BDC= angle ABD= 12°

similarly angle ADB= Angle CBD= 38°

angle ABC = 38+12= 50°

Jobisdone [24]3 years ago
5 0
Irssss i think it’s 50
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X-4y=-21<br> 8y-x=45<br> Solve the system <br> (X,y)=
meriva

Answer:

\displaystyle (3, 6)

Step-by-step explanation:

{x -4y = −21

{8y - x = 45

_________

\displaystyle \frac{4y}{4} = \frac{24}{4} \\ \\

\displaystyle y = 6[Plug this back into both equations above to get the x-coordinate of 3]; \displaystyle 3 = x

I am joyous to assist you anytime.

6 0
4 years ago
Which numbers below are integers but not natural numbers?<br><br> 1, - 5.41,3root12, 0, -3, -9/7,23
m_a_m_a [10]

Answer:

0 and -3

Step-by-step explanation:

Natural numbers are all whole numbers from 1 to infinity. i.e

1, 2, 3, 4 . . .

These numbers do not include 0.

Integers are all whole numbers (positive and negative) including 0. i.e

. . ., -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, . . .

These numbers are all natural numbers including their negative counterparts (i.e negatives of the natural numbers) and also 0.

<em>So from the options in the question:</em>

1 is a natural number as well as an integer

-5.41 is not a natural number neither is it an integer.

3 root 12 (written as 3\sqrt{12}) is neither a natural nor an integer number.

0 is an integer but not a natural number

-3 is an integer but not a natural number

-9/7 is neither a natural nor an integer number.

23 is a natural number as well as an integer

Therefore, 0 and -3 are integers but not natural numbers

8 0
3 years ago
Find the length of side AB
Ira Lisetskai [31]
In a triangle ABC, the length of AB is 16 inches.
3 0
3 years ago
2x - 3y = -14<br> 5x + 9y = -2
Firlakuza [10]

Step-by-step explanation:

2x-3y= -14

5x+9y= -2

multiply the first one by 5 and the second one by -2 to get equal and opposite value of x.

➡️when you multiply,it will be

10x-15y= -70

-10x-18y= 4

cancel out each x value,then you get

-15y-18y= -70+4

-33y= -66, divide each side by -33 to get the value of y

⚪️y= 2

➡️substitute the value of y in the equation of (2x-3y= -14) to find the value of x

2x-3(2)= -14

2x-6= -14

2x= -14+6

2x= -8 divide both side by 2

⚪️x= -4

so the answer is (-4,2)

8 0
3 years ago
The coordinates of the vertices of ANGLE PQR are P(-3,3), Q(2,3), and R(-3,-4). Find the side lengths to the nearest hundredth a
Marat540 [252]
<span>
Answer: PQ=5, QR=radical 61= 7.81, angle: 50degrees,</span>Why:PQ=|-3|+2=5PR=6<span>angle Alfa, so there is right angle triangle PQR so I can use following formula:</span>PQ^2 + RP^2=QR^2;25 + 36=QR^2;QR=radical 61<span>also I can use: sinus (angle)=PR/QR;</span><span>sin(angle)=6/radical61=0.76822 which gives angle to be little bit more than 50 degrees{sinus 50 degrees=<span>0,7660</span>}. </span>
7 0
3 years ago
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