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nadya68 [22]
3 years ago
8

Find the 8th term of the arithmetic sequence -5x+3, x+9, 7x+15, ...

Mathematics
1 answer:
Vadim26 [7]3 years ago
6 0

Answer:

Step-by-step explyou have a big brother or sister

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How to find the value of this expression
nevsk [136]
32 because 64 divided by 2 equals 32
8 0
3 years ago
Read 2 more answers
Write an equation for the translation of x^2+y^2=25 by 7 units left and 2 units down
soldi70 [24.7K]
Your equation is a circle where the center is the origin (0, 0) and the radius is 5. With the translation, the new center is (- 7, - 2). Radius stays the same. 

Your new equation is:

(x + 7)² + (y + 2)² = 25
4 0
3 years ago
The measure of the supplement of an angle is three times the measure of the
gtnhenbr [62]
<h2>Answer:</h2>

<h3><em>x=45degrees</em></h3>

<h2>Step-by-step explanation:</h2>

Let the angle to be solved be x

Let the supplement/compliment by y

x+y=90 Complimentary angles add up to 90 degrees.

x+3y=180 Supplementary angles add up to 180 degrees, the other angle is thrice the other compliment.

Evaluating this as a system:

x+y=90 Isolate x:

x=90−y Input into the other equation:

(90−y)+3y=180 Combine like terms, isolate y and its coefficients:

2y=90 Isolate y

y=45 Input into the first equation:

x+45=90 Isolate x:

x=45degrees

5 0
3 years ago
Can someone please help me I’ll give brilliant thingy
cricket20 [7]

Answer:

Yes, the shapes are similar. Note, the angles are equivalent and the sides are scales of each other satisfying the requirements for similarly.

Step-by-step explanation:

For a shape to be similar there are two conditions that must be met. (1) Must have equivalent angles (2) Sides must be related by a scalar.

In the two triangles presented, the first condition is met since each triangle has three angles, 90-53-37.

To test if the sides are scalar, each side must be related to a corresponding side of the other triangle with the same scalar.

9/6 = 3/2

12/8 = 3/2

15/10 = 3/2

Alternatively:

6/9 = 2/3

8/12 = 2/3

10/15 = 2/3

Since the relationship of the sides is the scalar 3/2 (Alternatively 2/3), then we can say the triangles meet the second condition.

Given that both conditions are satisfied, then we can say these triangles are similar.

Note, this is a "special case" right triangle commonly referred to as a 3-4-5 right triangle.

Cheers.

8 0
3 years ago
Why does (x-2)^2+9=0 have no real solutions?
alex41 [277]

Answer:

see explanation

Step-by-step explanation:

Given

(x - 2)² + 9 = 0 ( subtract 9 from both sides )

(x - 2)² = - 9  ( take the square root of both sides )

x - 2 = ± \sqrt{-9}

\sqrt{-9} yields no real solutions

There is no real number when multiplied by itself gives - 9

In fact the solutions to \sqrt{-9} are said to be imaginary, that is ± 3i

where i = \sqrt{-1}

If interested investigate further.

7 0
3 years ago
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