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aliina [53]
3 years ago
12

3x+2y I don't get need help

Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0
Where is the rest of the problem
You might be interested in
Which conic's equation has 2 squares with the same signs and different leading coefficients?
Romashka [77]

We want to see which is the conic equation that has 2 squares with the same sign and different leading coefficients.

We will see that it is the equation of the ellipse.

Now let's see why that is the correct answer.

The general conic equation is of the form:

A*(x - a)^2 + B*(x - b)^2 = R^2

Where A and B are the leading coefficients, (a, b) is the center of the figure, and R is the average radius of the figure.

For example, if A = B, this would be the equation of a circle, but we must have two different leading coefficients.

If we write:

A = 1/C

B = 1/K

(both are positive, because "it has two squares with the same signs").

Then we get the equation:

\frac{ (x - a)^2}{C} + \frac{(x - b)^2}{K} = R^2

We get the equation we wanted.

The same sign in both square parts and different leading coefficients.

The above equation is the general equation of an ellipse.

If you want to learn more, you can read:

brainly.com/question/10311514

7 0
2 years ago
NEED HELP ASAP!!! Will give brainliest!!!
Gekata [30.6K]

Answer:

1, 4/5,2/5

Step-by-step explanation:

y = 5x

Let y = 5

5 = 5x

Divide by 5

5/5 =5x/5

1=x

Let y=4

4 =5x

Divide by 5

4/5 =5x/5

4/5 =x

Let y=2

2 =5x

Divide by 5

2/5 =5x/5

2/5 =x

5 0
4 years ago
The ratio of the measures of the three angles in
julia-pushkina [17]

Answer:

24, 48, 108

Step-by-step explanation:

2:9:4

2x+9x+4x=180

15x=180

x=12

2(12)=24

9(12)=108

4(12)=48

3 0
2 years ago
At which values of x does the function F(x) have a vertical asymptote? Check all that apply. F(x)=2/3x(x-1)(x 5).
Alekssandra [29.7K]

The function F(x) have a vertical asymptote at x =0 and x =1.

Given that

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

We have to determine

At which value the function F(x) has a vertical asymptote.

According to the question

The given Function;

\rm  F(x)=\dfrac{2}{3x(x-1)(x^ 5)}

The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:

Then,

\rm 3x (x-1) (x^5)= 0

\rm x^5 =0, \ \  x=0\\\\ x-1 = 0, \ \ x =1\\

The value of x is 0 and 1.

Hence, the function F(x) have a vertical asymptote at x =0 and x =1.

To know more about Parabola click the link given below.

brainly.com/question/12868913

7 0
2 years ago
Round 4.88 to the nearest tenth
Minchanka [31]
4.88 rounded to the nearest tenth is 4.9
7 0
3 years ago
Read 2 more answers
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