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2 years ago

Slove (3x-2)=(2x-1)/(2) show step by step

Mathematics

2 answers:

shusha [124]2 years ago

3 0

Answer:

x= 3/4

Step-by-step explanation:

$(3x - 2) = \frac{(2x-1)}{2}$

2(3x - 2) = (2x - 1)

6x - 4 = 2x -1

4x = 3

x= 3/4

Lorico [155]2 years ago

3 0

Answer:

x=3/4

Step-by-step explanation:

Remove parentheses.

3x-2=\frac{2x-1}{2}3x−2=22x−1

Multiply both sides by 22.

6x-4=2x-16x−4=2x−1

Add 44 to both sides.

6x=2x-1+46x=2x−1+4

Simplify 2x-1+42x−1+4 to 2x+32x+3.

6x=2x+36x=2x+3

Subtract 2x2x from both sides.

6x-2x=36x−2x=3

Simplify 6x-2x6x−2x to 4x4x.

4x=34x=3

Divide both sides by 44.

x=\frac{3}{4}x=43

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2 years ago

Tank a has a capacity of 9.5 gallons. 6 1/3 gallons of the tank's water are poured out. how many gallons of water are left in th

Advocard [28]

Answer:

Water left in tank is $3\frac{1}{6}$ gallons.

Step-by-step explanation:

Given :

Capacity of tank = 9.5 gallons $=\frac{95}{10}$

Water taken out of tank = $6\frac{1}{3}=\frac{19}{3}$ gallons

We have to find the water left in the tank.

Water left in the tank = Total capacity of tank - water taken out of tank

= $\frac{95}{10}-\frac{19}{3}$

Taking LCM of (3,10)= 30

$\Rightarrow \frac{95 \times 3-19 \times10}{30}$

Solving further, we get,

$\Rightarrow \frac{285-190}{30}$

$\Rightarrow \frac{95}{30}=\frac{19}{6}=3\frac{1}{6}$

Thus, Water left in tank is $3\frac{1}{6}$ gallons..

5 0

3 years ago

Read 2 more answers

Show me how to solve this, please.<br> <img src="https://tex.z-dn.net/?f=%282.7%20%2A%2010%5E%7B-5%7D%29%20%2F%20%289%20%2A%2010

rusak2 [61]

Answer:

Step-by-step explanation:

2.7 * 10 ^-5 / 9 * 10 ^-6

First divide the numbers

2.7 / 9 = .3

Then divide the exponents

10^-5 / 10 ^ -6

When we divide exponents we subtract

10^(-5 - -6) = 10 ^1

.3 * 10 ^1

But scientific notation has a number between 1 and less than 10

Move the decimal 1 place to the left, so we subtract 1 from the exponent

3 * 10 ^ (1-1)

3 * 10 ^0

8 0

2 years ago

Read 2 more answers

The breaking strengths of cables produced by a certain manufacturer have a mean µ, of 1850 pounds, and a standard deviation of 9

saul85 [17]

Answer:

We accept H₀. We do not have argument to keep the claim that the mean breaking strength has increased

Step-by-step explanation:

Normal Distribution

Population Mean μ₀ = 1850 pounds

Standard Deviation σ = 90 pounds

Type of test

Null Hypothesis H₀ ⇒ μ = μ₀

Alternative Hypothesis Hₐ ⇒ μ > μ₀

A one tail test (right)

n = 21 as n < 30 we use t-student table

degree of fredom 20

t = 2.845

Sample mean μ = 1893

Then, we compute t statistics

t(s) = [ 1893 - 1850 ] / 90/ √n

t(s) = 43 * 4,583 / 90

t(s) = 197,069 / 90

t(s) = 2,190

And we compare t and t(s)

t(s) = 2.190

t = 2.845

Then t(s) < t

We are in the acceptance zone, we accept H₀

5 0

2 years ago

An e-commerce research company claims that 60% or more graduate students have bought merchandise on-line at their site. A consum

Rasek [7]

Answer:

We accept H₀ we don´t have enough evidence to conclude that a consumer group position is correct

Step-by-step explanation:

We have a case of test of proportion, as a consumer group is suspicious of the claim and think the proportion is lower we must develop a one tail test (left tail) Then

1.- Test hypothesis:

Null hypothesis H₀ P = P₀

Alternative hypothesis Hₐ P < P₀

2.- At significance level of α = 0,05 Critical value

z(c) = -1,64

3.-We compute z(s) value as:

z(s) = ( P - P₀ )/ √P*Q/n where P = 44/80 P = 0,55 and Q = 0,45

P₀ = 0,6 and n = 80

Plugging all these values in the equation we get:

z(s) = ( 0,55 - 0,6 ) / √(0,2475/80)

z(s) = - 0,05/ √0,0031

z(s) = - 0,05/0,056

z(s) = - 0,8928

4.-We compare z(s) and z(c)

z(s) > z(c) -0,8928 on the left side it means that z(s) is in the acceptance region so we accept H₀

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3 years ago