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2 years ago

Slove (3x-2)=(2x-1)/(2) show step by step

Mathematics

2 answers:

shusha [124]2 years ago

3 0

Answer:

x= 3/4

Step-by-step explanation:

$(3x - 2) = \frac{(2x-1)}{2}$

2(3x - 2) = (2x - 1)

6x - 4 = 2x -1

4x = 3

x= 3/4

Lorico [155]2 years ago

3 0

Answer:

x=3/4

Step-by-step explanation:

Remove parentheses.

3x-2=\frac{2x-1}{2}3x−2=22x−1

Multiply both sides by 22.

6x-4=2x-16x−4=2x−1

Add 44 to both sides.

6x=2x-1+46x=2x−1+4

Simplify 2x-1+42x−1+4 to 2x+32x+3.

6x=2x+36x=2x+3

Subtract 2x2x from both sides.

6x-2x=36x−2x=3

Simplify 6x-2x6x−2x to 4x4x.

4x=34x=3

Divide both sides by 44.

x=\frac{3}{4}x=43

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Answer:

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I HOPE THIS HELPS :)

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1 year ago

Read 2 more answers

An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume

Lynna [10]

Answer:

a) $21-2.58\frac{52}{\sqrt{350}}=13.83$

$21+2.58\frac{52}{\sqrt{350}}=28.17$

So on this case the 99% confidence interval would be given by (13.83;28.17)

b) $ME=2.58\frac{52}{\sqrt{350}}=7.17$

c) $ME=2.58\frac{52}{\sqrt{100}}=13.42$

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

$\bar X=21$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=52$ represent the population standard deviation

n=350 represent the sample size

99% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$21-2.58\frac{52}{\sqrt{350}}=13.83$

$21+2.58\frac{52}{\sqrt{350}}=28.17$

So on this case the 99% confidence interval would be given by (13.83;28.17)

Part b

The margin of error is given by:

$ME=2.58\frac{52}{\sqrt{350}}=7.17$

Part c

The margin of error is given by:

$ME=2.58\frac{52}{\sqrt{100}}=13.42$

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

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