The first example has students building upon the previous lesson by applying the scale factor to find missing dimensions. This leads into a discussion of whether this method is the most efficient and whether they could find another approach that would be simpler, as demonstrated in Example 2. Guide students to record responses and additional work in their student materials.
§ How can we use the scale factor to write an equation relating the scale drawing lengths to the actual lengths?
!
ú Thescalefactoristheconstantofproportionality,ortheintheequation=or=!oreven=
MP.2 ! whereistheactuallength,isthescaledrawinglength,andisthevalueoftheratioofthe drawing length to the corresponding actual length.
§ How can we use the scale factor to determine the actual measurements?
ú Divideeachdrawinglength,,bythescalefactor,,tofindtheactualmeasurement,x.Thisis
! illustrated by the equation = !.
§ How can we reconsider finding an actual length without dividing?
ú We can let the scale drawing be the first image and the actual picture be the second image. We can calculate the scale factor that relates the given scale drawing length, , to the actual length,. If the actual picture is an enlargement from the scale drawing, then the scale factor is greater than one or
> 1. If the actual picture is a reduction from the scale drawing, then the scale factor is less than one or < 1.
Scaffolding:
A reduction has a scale factor less than 1, and an enlargement has a scale factor greater than 1.
Lesson 18: Computing Actual Lengths from a Scale Drawing.
Answer:
The quotient of n and 6 is n/6, as quotient means divide.
for example, if it was "the quotient of 24 and 6", it would be 24/6, which is 4.
Hello from MrBillDoesMath!
Answer:
Number marbles >= 5
Discussion:
The only certain thing we can say is the jar contains at least 5 (green) marbles. The table shows probabilities, not certainties, and is no guarantee that any other marbles even exist in the jar,
Thank you,
MrB
Answer:
Step-by-step explanation:
First at all, we need to use 
to convert this expression into a fraction, like:
to convert into 
.
Expand the fraction to get the least common denominator, like
Write all numerators above the common denominator, like this:
The bottom one used the same way to became simplest form, like this:
And it became like this:
Now, we are going to simplify this complex fraction. We can use cross- multiply method to simplify this fraction.
3y-2(5) and 5y-1(3)
and it will becomes like this in function form:
Then, we should distribute 5 through the parenthesis
And.... Here we go. That is the answer.
