For this simulation, there are 5 numbers that we can draw. One of the numbers will result in seeing the groundhog. (1/5 or 0.20) To find the probability that Jay will see the groundhog 4 years in a row, we would use the following equation: 1/5•1/5•1/5•1/5 We would multiply the odds of getting a certain outcome by the number of time we want that outcome. The odds that Jay will see the groundhog for the next for years is 0.0016, or .16%.
