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2 years ago

(WILL GIVE BRAINLIEST) Find the mean for the data shown below.

Mathematics

2 answers:

Jlenok [28]2 years ago

8 0

Answer:

The mean is 2.0909090909091

Step-by-step explanation:

Mean: The average of all numbers.

First I added all of the numbers, and then divided by the amount of numbers there were.

1 + 1 + 1 + 1 + 1 + 2 + 2 + 3 + 3 + 3 + 5 = 23

23 ÷ 9 = 2.0909090909091

Rounded it's 2, or 2.09

gizmo_the_mogwai [7]2 years ago

3 0

Answer:

Step-by-step explanation:

17+3=20/2

mean=10

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You go for a run on monday you run 2.41Km on tuesday you ran the same distance how far did you ran altogether

FrozenT [24]

Answer: 4.82 km

Step-by-step explanation:

You went for a run on Monday.

You then went on a run on Tuesday as well. On this day you ran 2.41 km and it is said that you ran the same distance on both days which means you ran for 2.41 km on Monday as well.

The total distance you ran is therefore:

= 2.41 + 2.41

= 4.82 km

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2 years ago

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3 years ago

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3 years ago

Y=-6x-2, y=-6x-2 how many solutions are in it

GuDViN [60]

Answer:

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Step-by-step explanation:

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1 year ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$