Answer:
m`1 = 43` 2,3
m<2 1/12*
and m <3 = 1,3/2
Step-by-step explanation:
You would use PEMDAS
But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57
Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57
Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57
Now you can add all of the numbers together
32➕504=536
536➕57=593
Your answer is 593
Hope this helps! :3
Answer:
A
Step-by-step explanation:
Since the triangle is right use Pythagoras' identity to find EF
The square on the hypotenuse is equal to the sum of the squares on the other two sides, that is
EF² + DF² = DE² ← substitute values
EF² + 12² = 18², that is
EF² + 144 = 324 ( subtract 144 from both sides )
EF² = 180 ( take the square root of both sides )
EF = 
→ A
Answer:
<h2>x = -49</h2>
Step-by-step explanation:
x - 6 = -55 <em>add 6 to both sides</em>
x - 6 + 6 = -55 + 6
x = -49
