3 years ago

Anyone know the answer?

Mathematics

1 answer:

balu736 [363]3 years ago

5 0

Answer:

segment BC is located at B (1, 0) and C (1, 3) and is one-half the size of segment B C .

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katie gives maggie half of her pencils maggie keeps five pencils and gives the rest to jamil how many pencils did katie have if

g100num [7]

Answer:

12 pencils

Step-by-step explanation:

5 + 1 = 50% of the original amount

5 + 1 = 6

50% = 6

6 x 2 = 12 = 100%

Katie had 12 pencils

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3 years ago

Can someone help me with this question?

Dmitrij [34]

A rhombus would answer your question. Hope this helped sorry if im wrong.

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3 years ago

Express 0.875 as a fraction

Marina CMI [18]

7/8 is the answer you're looking for

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3 years ago

Fill in each blank so that the resulting statements are true.The vertices of The foci are located at ____.

stealth61 [152]

Given equation is

$\frac{x^2}{9}-\frac{y^2}{16}=1$

It can be written as follows.

$\frac{x^2}{3^2}-\frac{y^2}{4^2}=1$

Which is of the form

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$

where a=3 and b=4.

We know that the coordinates of the vertices are (a,0) and (-a,0)

Substitute a=3, we get

The vertices are (3,0) and (-3,0).

We know that the coordinates of the foci are (c,0) and (-c,0)

$c=\sqrt[]{a^2+b^2}$

Substitute a=3 and b=4, we get

$c=\sqrt[]{3^2+4^2}=\sqrt[]{9+16}=\sqrt[]{25}=5$

Substitute c=5, we get

Hence the foci are (5,0) and (-5,0).

5 0

1 year ago

Find the indicated term of the given geometric sequence. a1 = 14, r = –2, n = 11

Vesnalui [34]

Answer:

$a_{11} = 14336$

Step-by-step explanation:

The general formula for the twelfth term of a geometric sequence is:

$a_n = a_1(r)^{n-1}$

Where $a_1$ is the first term and r is the common ratio

In this case we know that:

$a_1 = 14\\r=-2$

The equation is:

$a_n = 14(-2)^{n-1}$

So for $n = 11$ we look for $a_{11}$

$a_{11} = 14(-2)^{11-1}$

$a_{11} = 14(-2)^{10}$

$a_{11} = 14336$

4 0

3 years ago

Read 2 more answers