Answer:
if you are including the tip it is $24 I think
the Pythagorean Theoremproof of let ΔABC be a right triangle. and sinA=a/c, and cosA= b/ca opposite side of the angle Ab the adjacent side of the angle Aand c is the hypotenuswe know that sin²A +cos²A= (a/c)²+ (b/c) ², but sin²A +cos²A=1so, a²/c²+ b²/c ²=1 which implies a²+ b²=c² the answer is Transitive Property of Equality proof the right triangles BDC and CDA are siWe start with the original right triangle, now denoted ABC, and need only one additional construct - the altitude AD. The triangles ABC, DBA, and DAC are similar which leads to two ratios:AB/BC = BD/AB and AC/BC = DC/AC.Written another way these becomeAB·AB = BD·BC and AC·AC = DC·BCSumming up we getAB·AB + AC·AC= BD·BC + DC·BC = (BD+DC)·BC = BC·BC.so not in the proof is Transitive Property of Equality
Answer:
x = 49
Step-by-step explanation:
Given
= 
( cross- multiply )
5(x - 16) = 3(x + 6) ← distribute parenthesis on both sides
5x - 80 = 3x + 18 ( subtract 3x from both sides )
2x - 80 = 18 ( add 80 to both sides )
2x = 98 ( divide both sides by 2 )
x = 49
Answer:
All of them
Step-by-step explanation:
