Answer:
1st one m=0
y= <u>0.49875311x / cm </u>
<u>No horizonal asymptotes</u>
<u>x= 1/2 + 2.005 mcy</u>
<u />
<u>2nd one is </u>
<u>slope 1/2</u>
<u>y intercept (0,2)</u>
<u />
<u>x y</u>
<u>-4 0</u>
<u>0 2</u>
<u />
Step-by-step explanation:
for 2
starting point ay y 2 make a point
then rise over run
go up 1 and to the right 2 and point , then up 1 and to the right 2 and point
there is your graph
Answer:
a. 
.
b. 
Step-by-step explanation:
By the definition, the expected value of a random variable X with probability mass function p is given by 
where the sum runs over all the posible values of X. Given a function g, the random variable Y=g(X) is defined. Note that the function g induces a probability mass function P' given by P'(Y=k) = P(X=g^{-1}(k)) when the function g is bijective.
a. Note that for 1/3ln(2)+1/6ln(5) by choosing the function g(x) = ln(x) the expression coincides with E(g(x)), because if Y = g(x) then E(Y) = P'(Y=1)*ln(1)+P'(Y=2)*ln(2)+P'(Y=5)*ln(5) = P(X=1)*ln(1)+P(X=2)*ln(2)+P(X=5)*ln(5).
b. On the same fashion, the function g(x) = xe^{xt} fullfills the expression of E[g(X)]
