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Radda [10]
3 years ago
15

What is the area of the trapezoid?

Mathematics
2 answers:
Assoli18 [71]3 years ago
3 0

Answer:

a+b/2×h=56

Step-by-step explanation:

thanks needed.......

Anni [7]3 years ago
3 0
I believe it would be 56
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165:250 as a decimal
Klio2033 [76]
You have to divide the two numbers, which will give you 1.5151515151... So if you round It will give you: 1.51
5 0
3 years ago
Read 2 more answers
EASY MATH QUESTION <br><br> PLEASE HELP
Juli2301 [7.4K]
F(x)=3x^2-5 when x=-11
f(-11)=3(-11)^2-5
f(-11)=-33^2-5
f(-11)=1089-5
f(-11)= 1084

Hope this could help!
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=r%20-%207%20%3D%207%20What%20ir%20r" id="TexFormula1" title="r - 7 = 7 What ir r" alt="r - 7 =
Art [367]
R-7=7 add the seven from both sides, leaving the r alone, because this is what you are trying to find. Thus the answer is r=14.

8 0
4 years ago
The length of a rectangle is "a" inches and the width is 3 inches more than its length. find the perimeter and the area
Alex73 [517]

Answer:

Step-by-step explanation:

Givens

Length = a

Width = a + 3

Formulas

P = 2L + 2w

Area = L * w

Solution

Perimeter

P = 2L +  2w

P = 2*a + 2(a + 3)             Remove the Brackets

p = 2a + 2a + 6                Combine

<u><em>P = 4a + 6</em></u>

Area

Area = L * w

Area = a (a + 3)

<u><em>Area = a^2 + 3a</em></u>

7 0
2 years ago
How many solutions does this equation have x^4 - 6x^2 -7 = 0
NNADVOKAT [17]

Answer:

2 solutions

Step-by-step explanation:

x^4-6x^2-7=0

Replace x^2 by y

(x^2)^2-6x^2-7=0

y^2-6y-7=0

D=b^2-4ac= (-6)^2-4*1*(-7)= 36+28=64

sqrtD=8

y1=(-b-sqrtD)/2a=-2/2=-1

y2= (-b+sqrtD)/2a=14/2=7

x^2=-1(n0 roots)    x^2=7 x=sqrt7 or x=-sqrt7

2 roots

5 0
3 years ago
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