<h3>Answer: A) 1</h3>
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Explanation:
Let's label each pair of outcomes as an ordered pair (x,y)
x = first spinner outcome
y = second spinner outcome
We have these 12 different possible combos
(1,3), (1,4), (1,5), (1,6)
(2,3), (2,4), (2,5), (2,6)
(3,3), (3,4), (3,5), (3,6)
Focus on the third column where y = 5 for each (x,y) pair. Of this column only (2,5) has x be an even number. The other results in that column have x be odd.
Basically (1,5) is the only possible outcome if we want the first spinner to lan on an even number, and the second spinner to land on 5.
</h2><h2>3.</h2><h2>
</h2><h2>Hope it Helps❤</h2>
