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Elena-2011 [213]
2 years ago
10

Hellppp please ill give brainlesst

Mathematics
1 answer:
ser-zykov [4K]2 years ago
6 0

Answer: I got this-- its me again..  It's D again- I explained this time tho-

Step-by-step explanation:

2 cm represents 100 miles, then 1 cm represents 50 miles and .5 cm represents 25 miles.

Town A = 175 miles from town B.

Town C = 100 miles from town B.

SO, Town A is 175 miles + 100 miles = 275 miles from town C.

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Solve the system of equations 3x + y = 3 and 7x + 2y = 1.
vodka [1.7K]

Answer:

  (x, y) = (-5, 18)

Step-by-step explanation:

You have done the first two steps.

<h3>3.</h3>

  7x +2(3 -3x) = 1 . . . . . equation with y substituted

  7x +6 -6x = 1 . . . . . . . eliminate parentheses using the distributive property

  x = -5 . . . . . . . . . . . . . subtract 6 from both sides, collect terms

<h3>4.</h3>

  y = 3 -3(-5) . . . . . . . . use the substitution equation to find y

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The solution is (x, y) = (-5, 18).

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2 years ago
Factorise: a^2 + 8a - 20
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That would be
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8 0
3 years ago
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A 4-foot tall child walks directly away from a 12-foot tall lamppost at 2 mph. How quickly is the length of her shadow increasin
xz_007 [3.2K]

Answer:

The length of the shadow is increasing with the rate of 1.5 feet per sec

Step-by-step explanation:

Let AB and CD represents the height of the lamppost and child respectively ( shown below )

Also, let E be a point represents the position of child.

In triangles ABE and CDE,

\angle ABE\cong \angle CDE    ( right angles )

\angle AEB\cong \angle CED  ( common angles )

By AA similarity postulate,

\triangle ABE\sim \triangle CDE

∵ Corresponding sides of similar triangles are in same proportion,

\implies \frac{AB}{CD}=\frac{BE}{DE}

We have, AB = 12 ft, CD = 4 ft, BE = BD + DE = 6 + DE,

\implies \frac{12}{4}=\frac{6+DE}{DE}

12DE = 24 + 4DE

8DE = 24

DE=3

Now, the speed of walking = 2 mph = \frac{2\times 5280}{3600}\approx 2.933\text{ ft per sec}

Note: 1 mile = 5280 ft, 1 hour = 3600 sec

Thus, the time taken by child to reach at E  

= \frac{\text{Walked distance}}{\text{Walking speed}}

=\frac{6}{2.933}

= 2.045 hours

Hence, the change rate in the length of shadow

= \frac{\text{Length of shadow}}{\text{Time taken}}

=\frac{3}{2.045}

= 1.5 ft per sec.

3 0
3 years ago
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maw [93]
The correct answer is 2.5. Not too sure how to get that answer but my math test had this question and that was the answer.
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