All categories

2 years ago

How do i factor (6x+3x)(12x-24x+36)

Mathematics

1 answer:

riadik2000 [5.3K]2 years ago

7 0

-108x(x-3) I’m pretty sure

You might be interested in

How do i do this or what's the answer (there is a picture btw)

velikii [3]

AB is 6
BC is 4
CD is 6
DA is 8
A is 45degrees
B is 130dgrees
C is 130degrees
D is 45degrees (about)

5 0

3 years ago

Suppose I have an urn with 9 balls: 4 green, 3 yellow and 2 white ones. I draw a ball from the urn repeatedly with replacement.

Mrrafil [7]

Answer:

$E(X_n)=\frac{2(n-1)}{27}$

$E(y)=\frac{14}{9}$

Step-by-step explanation:

From the question we are told that:

Sample size n=9

Number of Green $g=4$

Number of yellow $y=4$

Number of white $w=4$

Probability of Green Followed by yellow P(GY) ball

$P(GY)=\frac{4}{9}*\frac{3}{9}$

$P(GY)=\frac{4}{27}$

Generally the equations for when n is even is mathematically given by

$Probability of success P(S)=\frac{4}{27}$

$Probability of Failure P(F)=\frac{27-4}{27}$

$Probability of Failure P(F)=\frac{23}{27}$

Therefore

$E(X_n)=\frac{n}{2}*P$

$E(X_n)=\frac{n}{2}*\frac{4}{27}$

$E(X_n)=\frac{2n}{27}$

Generally the equations for when n is odd is mathematically given by

$\frac{n-1}{2}$

$E(X_n)=\frac{n-1}{2}*\frac{4}{27}$

$E(X_n)=\frac{2(n-1)}{27}$

Probability of drawing white ball

$P(w)=\frac{2}{9}$

Therefore

$E(w)=\frac{1}{p}$

$E(w)=\frac{1}{\frac{2}{9}}$

$E(w)=\frac{9}{2}$

Therefore

$E(y)=[E(w)-1]\frac{4}{9}$

$E(y)=[\frac{9}{2}-1]\frac{4}{9}$

$E(y)=\frac{14}{9}$

5 0

3 years ago

SIERENCE

Svetllana [295]

B for sure because yes

8 0

3 years ago

In a grocery store a $21 case of toilet paper is labeled, "Get a 20% discount." What is the discount? What is the sale price of

arsen [322]

Hi There!

Step-by-step explanation and Answer:

21 * 0.2 = $4.2 (Discount)

21 - 4.2 = $16.8 (Sale Price)

Hope This Helps :)

5 0

3 years ago

Read 2 more answers

The numbers 1 through 15 are written on cards. One card is chosen at random. Event A is choosing a

lana [24]

Step-by-step explanation:

the probability is always the number of desired cases over the number of all possible cases.

in our situation we have 15 cards.

that is the total possible cases when a random card is chosen.

how many desired cases do we have ?

a number NOT a multiple of 5.

how many are there ?

it is easier to say how many numbers there are being a multiple of 5 : 5, 10, 15

so, 3 numbers out of the 15 are multiple of 5.

that means

15 - 3 = 12 numbers of the 15 are NOT multiples of 5.

so, the probability to draw a card that is not a multiple of 5 is

12/15 = 4/5 = 0.8

the information about event B and even numbers is irrelevant for the question.

6 0

1 year ago