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3 years ago

-1 1/3 plus 3/4 (fraction form)

Mathematics

2 answers:

katen-ka-za [31]3 years ago

6 0

Answer:

$\boxed{-\frac{7}{12} }$

Step-by-step explanation:

$-1\frac{1}{3} +\frac{3}{4}$

→ Make both denominators the same

$-1\frac{1}{3} +\frac{3}{4}=-1\frac{4}{12} +\frac{9}{12}$

→ Convert mixed number into improper fraction

$-1\frac{1}{3} +\frac{3}{4}=-1\frac{4}{12} +\frac{9}{12}=-\frac{16}{12} +\frac{9}{12}$

→ Do the -16 + 9 and leave 12 as the denominator

$-1\frac{1}{3} +\frac{3}{4}=-1\frac{4}{12} +\frac{9}{12}=-\frac{16}{12} +\frac{9}{12}=-\frac{7}{12}$

Bumek [7]3 years ago

3 0

Answer:

7/12

Step-by-step explanation:

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Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

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$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

3 years ago

What is six more than twice a number x

natta225 [31]

Answer:

2x + 6

2 times the number x is 2x (2 times x)

six more than that would be +6

5 0

3 years ago

9.6x10^85/3x10^63 in scientific notation

Novosadov [1.4K]

Answer:

3.27*10^22

Step-by-step explanation:

Given the expression 9.6x10^85/3x10^63, we are to write it on scientific notation as shown:

9.6x10^85/3x10^63

= (9.8/3) * (10^85/10^63)

= (9.8/3) * 10^{85-63}

= (9.8/3) *10^22

= 3.27 *10^22

Hence the expression in scientific notation is 3.27*10^22

6 0

2 years ago

1. Mrs. Verner's class has

Gemiola [76]

Answer:

46.7%

Step-by-step explanation:

Given:

Total number of students in Mrs. Verner's class = 15

Number of girls = 8

To find: percentage are boys

Solution:

Percentage of boys = ( Number of boys / Total number of students ) × 100

Number of boys = Total number of students - Number of girls = 15 - 8 = 7

So,

Percentage of boys = × 100 = 46.7%

4 0

2 years ago

Please help it is due in 20 minutes and i still have like 5 questions!!!

OverLord2011 [107]

Answer:

$42.50

Step-by-step explanation:

multiply 50 by 0.15 and get 7.50 subtract from 50

8 0

3 years ago

Read 2 more answers