For this case we have that the following function complies with the given conditions:
To prove it, let's find the roots of the polynomial:
By doing common factor 3 we have:
Factoring the second degree polynomial we have:
Then, the solutions are:
Solution 1:
Solution 2:
Answer:
A second degree polynomial function f (x) that has a lead coefficient of 3 and roots 4 and 1 is:
Hope it helped! I have to use 20 characters sooooooo
Ok bro, this is 2 but like i speak english
Answer:
0.101
Step-by-step explanation:
well because it has a tenth numeral which makes it greater
crosses x-axis at (2, 0 ) and y-axis at (0, - 4 )
To find where the graph crosses the x and y axes ( intercepts )
• let x = 0, in the equation for y- intercept
• let y = 0, in the equation for x- intercept
x = 0 : y = 0 - 4 = - 4 ⇒ (0, - 4 )
y = 0 : 2x - 4 = 0 ⇒ 2x = 4 ⇒ x = 2 ⇒ (2, 0 )
