Answer:$57
Step-by-step explanation:
$267-$33=$234
$234-$65=$169
$169-$112=$57
the coordinates where the bridges must be built is
and
.
<u>Step-by-step explanation:</u>
Here we have , a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream at point A and then again at point B. Bridges must be built at those points.We need to find Identify the coordinates where the bridges must be built. Let's find out:
Basically we need to find values of x for which f(x) = g(x) :
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Value of g(x) at x = 3 : y=3x -15 = 3(3)-15 = -6
Value of g(x) at x = 6 : y=3x -15 = 3(6)-15 = 3
Therefore , the coordinates where the bridges must be built is
and
.
Answer:
the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
Step-by-step explanation:
since the volume of a cylinder is
V= π*R²*L → L =V/ (π*R²)
the cost function is
Cost = cost of side material * side area + cost of top and bottom material * top and bottom area
C = a* 2*π*R*L + b* 2*π*R²
replacing the value of L
C = a* 2*π*R* V/ (π*R²) + b* 2*π*R² = a* 2*V/R + b* 2*π*R²
then the optimal radius for minimum cost can be found when the derivative of the cost with respect to the radius equals 0 , then
dC/dR = -2*a*V/R² + 4*π*b*R = 0
4*π*b*R = 2*a*V/R²
R³ = a*V/(2*π*b)
R= ∛( a*V/(2*π*b))
replacing values
R= ∛( a*V/(2*π*b)) = ∛(0.03$/cm² * 600 cm³ /(2*π* 0.05$/cm²) )= 3.85 cm
then
L =V/ (π*R²) = 600 cm³/(π*(3.85 cm)²) = 12.88 cm
therefore the dimensions that minimize the cost of the cylinder are R= 3.85 cm and L=12.88 cm
Answer:

Step-by-step explanation:
From the attached figure, AB is the height of the satellite and the distance between Ethan and the ground is 1 mile.
We can find the angle of elevation from Ethan to the satellite using trigonometry as follows :

So, the angle of elevation is 80.53 degrees.