1.x^2 +6x - 4 = 6x
X^2 + 6x -4 - 6x = 0
X^2 - 4 = 0
By difference of two squares :
X^2 - 4 = 0 can be written as (x-2) (x+2) = 0
(X-2)=0 therefore x= 2
(X+2)=0 therefore x= -2
2. X^2 - 8x = -6x
X^2 -8x + 6x = 0
X^2 - 2x = 0
X(X-2) = 0
X= 0, X= 2
Answer:
a balance and a beaker of water
hope it helps mark as brainliest
![\bf \begin{array}{lllll} round(x)&\boxed{1}&2&3&\boxed{4}\\\\ wrestlers[f(x)]&\boxed{64}&32&18&\boxed{9} \end{array} \\\\\\ slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby \begin{array}{llll} average\ rate\\ of\ change \end{array}\\\\ -------------------------------\\\\ f(x)= \qquad \begin{cases} x_1=1\\ x_2=4 \end{cases}\implies \cfrac{f(4)-f(1)}{4-1}\implies \cfrac{9-64}{4-1}\implies \cfrac{-55}{3}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blllll%7D%0Around%28x%29%26%5Cboxed%7B1%7D%262%263%26%5Cboxed%7B4%7D%5C%5C%5C%5C%0Awrestlers%5Bf%28x%29%5D%26%5Cboxed%7B64%7D%2632%2618%26%5Cboxed%7B9%7D%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0Aslope%20%3D%20%7B%7B%20m%7D%7D%3D%20%5Ccfrac%7Brise%7D%7Brun%7D%20%5Cimplies%20%0A%5Ccfrac%7B%7B%7B%20f%28x_2%29%7D%7D-%7B%7B%20f%28x_1%29%7D%7D%7D%7B%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%7D%5Cimpliedby%20%0A%5Cbegin%7Barray%7D%7Bllll%7D%0Aaverage%5C%20rate%5C%5C%0Aof%5C%20change%0A%5Cend%7Barray%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0Af%28x%29%3D%20%20%20%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Ax_1%3D1%5C%5C%0Ax_2%3D4%0A%5Cend%7Bcases%7D%5Cimplies%20%5Ccfrac%7Bf%284%29-f%281%29%7D%7B4-1%7D%5Cimplies%20%5Ccfrac%7B9-64%7D%7B4-1%7D%5Cimplies%20%5Ccfrac%7B-55%7D%7B3%7D)
55 over 3, or 55 wrestlers for every 3 rounds, but the wrestlers value is negative, thus 55 "less" wrestlers for every 3 rounds on average.
With this line, we see that when x is a small negative number, F(x) is a very large negative number, or B.
Remember that F(x) is the same as y. And looking at the pattern of the line, the greater the negative x is, the smaller the negative y is.
